12. A proton in the solar wind travels perpendicularly at 3.00×10 m/s across the Earth's magnetic ficld lines. The field at that location is 0.0000100 T. a. Determine the magnitude of the magnetic force that will deflect the proton. (ans: 4.8 x 1019 N) b. Since this force acts at right angles to its velocity, the proton will experience this as a centripetal force, causing the proton to have a "corkscrew" circular motion. Calculate the radius of these circles as the proton travels through the field. (ans: 313 m)

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Need help with question 12 part a and b only please
12. A proton in the solar wind travels perpendicularly at 3.00×10 m/s across the Earth's magnetic field
lines. The field at that location is 0.0000100 T.
a.
Determine the magnitude of the magnetic force that will deflect the proton. (ans: 4.8 x 1019 N)
Since this force acts at right angles to its velocity, the proton will experience this as a
centripetal force, causing the proton to have a "corkscrew" circular motion. Calculate the
radius of these circles as the proton travels through the field. (ans: 313 m)
b.
2020-12-11
Page 10 of 17
Transcribed Image Text:12. A proton in the solar wind travels perpendicularly at 3.00×10 m/s across the Earth's magnetic field lines. The field at that location is 0.0000100 T. a. Determine the magnitude of the magnetic force that will deflect the proton. (ans: 4.8 x 1019 N) Since this force acts at right angles to its velocity, the proton will experience this as a centripetal force, causing the proton to have a "corkscrew" circular motion. Calculate the radius of these circles as the proton travels through the field. (ans: 313 m) b. 2020-12-11 Page 10 of 17
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