12. A 4-kg ball moving to the right at 12 m/s collides elastically with a 2-kg ball moving to the left at 6 m/s. What are the speeds of the 4-kg and the 2-kg balls after the collision? A) 4 m/s and 10 m/s B) 6 m/s and 12 m/s C) 12 m/s and 6 m/s D) 8 m/s and -8 m/s E) 10 m/s and -4 m/s

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12 please by using this formula shit easy way to explain
12. A 4-kg ball moving to the right at 12 m/s collides elastically with a 2-kg ball moving to the left at 6 m/s. What are the
speeds of the 4-kg and the 2-kg balls after the collision?
A) 4 m/s and 10 m/s
B) 6 m/s and 12 m/s
C) 12 m/s and 6 m/s
D) 8 m/s and -8 m/s
E) 10 m/s and -4 m/s
13. A 2-kg block is placed at the top of a 5-m high, frictionless ramp and is released from rest. At the bottom of the ramp
the 2-kg block collides with a 1-kg block that is initially at rest. The blocks stick together. What is the velocity of the
blocks after the collision?
A) 3.3 m/s
B) 6.6 m/s
C) 9.9 m/s
D) 10.10 m/s
E) There is not enough information given
14. A potential energy function is given below. At what point would an object experience a force in the positive x
direction?
U
a
b
A) a
B) b
C) с
D) d
E) in the region from 0 to a, and from c to infinity
15. A 3-kg box is moving at 6.0 m/s atop a hill that is 5.0 m above a flat frictionless surface. It descends the hill (also
frictionless) and at the bottom of the hill contacts an ideal spring, which compresses 1.53 m before stopping. What is the
spring constant k ?
A) 172 N/m
B) 225 N/m
C) 344 N/m
D) 450 N/m
E) 980 N/m
radius R= 0.5 m,
4. A wheel, with
ime it stops spinning about i
Transcribed Image Text:12. A 4-kg ball moving to the right at 12 m/s collides elastically with a 2-kg ball moving to the left at 6 m/s. What are the speeds of the 4-kg and the 2-kg balls after the collision? A) 4 m/s and 10 m/s B) 6 m/s and 12 m/s C) 12 m/s and 6 m/s D) 8 m/s and -8 m/s E) 10 m/s and -4 m/s 13. A 2-kg block is placed at the top of a 5-m high, frictionless ramp and is released from rest. At the bottom of the ramp the 2-kg block collides with a 1-kg block that is initially at rest. The blocks stick together. What is the velocity of the blocks after the collision? A) 3.3 m/s B) 6.6 m/s C) 9.9 m/s D) 10.10 m/s E) There is not enough information given 14. A potential energy function is given below. At what point would an object experience a force in the positive x direction? U a b A) a B) b C) с D) d E) in the region from 0 to a, and from c to infinity 15. A 3-kg box is moving at 6.0 m/s atop a hill that is 5.0 m above a flat frictionless surface. It descends the hill (also frictionless) and at the bottom of the hill contacts an ideal spring, which compresses 1.53 m before stopping. What is the spring constant k ? A) 172 N/m B) 225 N/m C) 344 N/m D) 450 N/m E) 980 N/m radius R= 0.5 m, 4. A wheel, with ime it stops spinning about i
v2
Circular motion: ac =
R
Fnet
W
Pavr =
At
ma;
Weight: Fg= mg, ;
g = 9.8 m/s?;
1
m v'; Potential energy: Ug = mgy
(Kinetic energy: K =
Ej = Er
E = U+K
v2
a, =
Rotational motion:
1 rev = 2t rad;
= o'r;
v = o r;
at = a r;
r
1
0 = 0o + at;
0 = 0o t +
at2;
2
2θα -ω - ω
K=
2
T= rFsino;
T=rxF;
1
Iaisk = mR 2
2
1
IyF
mR
2
Στ- Ια;
Ipoint mass = mr?
+
2
1
Ihoop = mR?
Irod(center) =
-mL²
Irod(end) =
mL?
Iball =
mR?
12
Ishell =
mR?
3
5
I= Icom + MD?
work: W=t0; K=-lo 2
dW
P =-
dt
2
W
Pavr =
At
W =
2
- 1o 2
1
-m Vcom
2
Rolling:
Veom = Ro
K =
Im
2.
T= f,R
F,max = H,Fn
Incline: F=mgsin0 F=mgcos0
Angular momentum:
Lpoint mass =m rxv
L=mrvsin 0;
L=m (rVy - ryVx)k
L= Io
m1X1+m2X2
m, +m2
LI = L
In 01 =I 202
X com =
mıy1+m2y2
Y com =
m1 +m2
Transcribed Image Text:v2 Circular motion: ac = R Fnet W Pavr = At ma; Weight: Fg= mg, ; g = 9.8 m/s?; 1 m v'; Potential energy: Ug = mgy (Kinetic energy: K = Ej = Er E = U+K v2 a, = Rotational motion: 1 rev = 2t rad; = o'r; v = o r; at = a r; r 1 0 = 0o + at; 0 = 0o t + at2; 2 2θα -ω - ω K= 2 T= rFsino; T=rxF; 1 Iaisk = mR 2 2 1 IyF mR 2 Στ- Ια; Ipoint mass = mr? + 2 1 Ihoop = mR? Irod(center) = -mL² Irod(end) = mL? Iball = mR? 12 Ishell = mR? 3 5 I= Icom + MD? work: W=t0; K=-lo 2 dW P =- dt 2 W Pavr = At W = 2 - 1o 2 1 -m Vcom 2 Rolling: Veom = Ro K = Im 2. T= f,R F,max = H,Fn Incline: F=mgsin0 F=mgcos0 Angular momentum: Lpoint mass =m rxv L=mrvsin 0; L=m (rVy - ryVx)k L= Io m1X1+m2X2 m, +m2 LI = L In 01 =I 202 X com = mıy1+m2y2 Y com = m1 +m2
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