#12 FET AMPLIFIERS AND SWITCHING CIRCUITSin%3DVDD(rms) when a 50 mV rms input is applied? gm = 5000 µS.+12 VFIGURE 9-60Multisim and LT Spice file circuitsare identified with a logo and are inRp1.5 k2SpiceC3the Problems folder on the website.V.Filenames correspond to figure num-bers (e.g., FGM09-60 or FGS09-60).10 µF0.1 µF10kNRsRG10 MQ1.0 kN1 µF15. Determine the voltage gain of each common-source amplifier in Figure 9-61.VDDVDDE 9-61A6+RDRDLTSpice2.2 k21.2 k2V.0.1 µF1 µFEm =3.8 mS22 kN0.1 µFEm=5.5 mS0.1 FRG4.7 MQRGUY OTC20.1 uF10 MQU 09(a)(b)16. Draw the dc and ac equivalent circuits for the amplifier in Figure 9-62.-62VDDRpSpiceV.1 µF 心6 mARp1.5 kN1.0 kNR110 k28 mARp1.0 k23 mAR24.7 kNRsRGRG10 M210 MQ(c)(b)(a)9. Identify each characteristic curve in Figure 9-59 by the type of FET that it represents.12AVGS+VGSGS-VGS(c)(a)(a)10. Refer to the JFET transfer characteristic curve in Figure 9-16(a) and determine the peak-to-peak value of I when Vos is varied +1.5 V about its Q-point value.8 mA.11. Repeat Problem 10 for the curves in Figure 9-16(b) and Figure 9-16(c).%3D12 y12. Given that Ip = 2.83 mA in Figure 9-60, find Vps and VGS. VGS(ofm = -7 V and Ipss13. If a 50 mV rms input signal is applied to the amplifier in Figure 9-60, what is the peak-to-peakoutput voltage? gm = .01%3D5000 uS.

12. The given figure 9-60 is shown below: It is given that: ID=2.83 mAVGSoff=VP-7 VIDSS=8 mA

Answered: +12 V RD 1.5 k2 C3 V out C1 10 μ Vin o…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Concept explainers

Question

#12

Transcribed Image Text:FET AMPLIFIERS AND SWITCHING CIRCUITS in %3D VDD (rms) when a 50 mV rms input is applied? gm = 5000 µS. +12 V FIGURE 9-60 Multisim and LT Spice file circuits are identified with a logo and are in Rp 1.5 k2 Spice C3 the Problems folder on the website. V. Filenames correspond to figure num- bers (e.g., FGM09-60 or FGS09-60). 10 µF 0.1 µF 10kN Rs RG 10 MQ 1.0 kN 1 µF 15. Determine the voltage gain of each common-source amplifier in Figure 9-61. VDD VDD E 9-61 A6+ RD RD LT Spice 2.2 k2 1.2 k2 V. 0.1 µF 1 µF Em =3.8 mS 22 kN 0.1 µF Em=5.5 mS 0.1 F RG 4.7 MQ RG UY OT C2 0.1 uF 10 MQ U 09 (a) (b) 16. Draw the dc and ac equivalent circuits for the amplifier in Figure 9-62. -62 VDD Rp Spice V. 1 µF

心
6 mA
Rp
1.5 kN
1.0 kN
R1
10 k2
8 mA
Rp
1.0 k2
3 mA
R2
4.7 kN
Rs
RG
RG
10 M2
10 MQ
(c)
(b)
(a)
9. Identify each characteristic curve in Figure 9-59 by the type of FET that it represents.
12A
VGS
+VGS
GS
-VGS
(c)
(a)
(a)
10. Refer to the JFET transfer characteristic curve in Figure 9-16(a) and determine the peak-to-
peak value of I when Vos is varied +1.5 V about its Q-point value.
8 mA.
11. Repeat Problem 10 for the curves in Figure 9-16(b) and Figure 9-16(c).
%3D
12 y
12. Given that Ip = 2.83 mA in Figure 9-60, find Vps and V
GS. VGS(ofm = -7 V and Ipss
13. If a 50 mV rms input signal is applied to the amplifier in Figure 9-60, what is the peak-to-peak
output voltage? gm = .01
%3D
5000 uS.

Expert Solution

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions