see pic attached 12) Circle O is tangent to L, 5x 12y + 19 =0 and L, : 5x 12y 7= 0. If the center of theCircle O is om Lx-3y+3 0, what is the equation of circle O?园0與直線L:5x-12y + 190-L:5x-12y-7%3D0均相切,且圓心0在直線L:x-3y+3=0上,請問圓0的方程為何?圓0與直線L,5x - 12y + 19 %3D0、L5x-12y-7=0均相切,且圓心0在直線L:x-3y + 3%=D0上,請問圓0的方程為何?(A) (x- 3)² +(y - 2)² =1(B) (x - 6) +(y - 3) =1(C) (x - 3)² +(y -2)? =132)² 313(D) (x- 6)² +(y - 3) =13

Name: see pic attached 12) Circle O is tangent to L, 5x 12y + 19 =0 and L, :
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: see pic attached 12) Circle O is tangent to L, 5x 12y + 19 =0 and L, : 5x 12y 7= 0. If the center of theCircle O is om Lx-3y+3 0, what is the equation of circle O?园0與直線L:5x-12y + 190-L:5x-12y-7%3D0均相切,且圓心0在直線L:x-3y+3=0上,請問圓0的方程為何?圓0與直線L,5x - 12y + 19