College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Concept explainers
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
Question
Q 11
![**Question 11**
A mass rotates at the end of a string, in the horizontal plane. If the string makes an angle of 30 degrees with the horizontal, and the string is 1.55 meters long, then the velocity of the mass is:
- ○ 4.12 m/s
- ○ 10.39 m/s
- ○ 7.878 m/s
- ○ 12.20 m/s
- ○ cannot solve without knowing the mass
- ○ NOTA (None of the Above)
---
**Question 12**
In the previous problem, now imagine that the person changes how they swing the mass so that the mass is swinging faster. In that case:
- ○ the mass becomes more vertical and the tension increases
- ○ the mass becomes more horizontal and the tension increases
- ○ the mass becomes more vertical and the tension decreases
- ○ the mass becomes more horizontal and the tension decreases
- ○ the tension is unchanged
- ○ NOTA (None of the Above)
---
*Note: NOTA stands for "None of the Above."*
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Transcribed Image Text:**Question 11**
A mass rotates at the end of a string, in the horizontal plane. If the string makes an angle of 30 degrees with the horizontal, and the string is 1.55 meters long, then the velocity of the mass is:
- ○ 4.12 m/s
- ○ 10.39 m/s
- ○ 7.878 m/s
- ○ 12.20 m/s
- ○ cannot solve without knowing the mass
- ○ NOTA (None of the Above)
---
**Question 12**
In the previous problem, now imagine that the person changes how they swing the mass so that the mass is swinging faster. In that case:
- ○ the mass becomes more vertical and the tension increases
- ○ the mass becomes more horizontal and the tension increases
- ○ the mass becomes more vertical and the tension decreases
- ○ the mass becomes more horizontal and the tension decreases
- ○ the tension is unchanged
- ○ NOTA (None of the Above)
---
*Note: NOTA stands for "None of the Above."*
At the bottom of the questions:
"Click Save and Submit to save and submit. Click Save All Answers to save all answers."
There are no visible graphs or diagrams accompanying these questions.
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