((11.4) Consider the molecule below. Determine the molecular geometry at each of the labelled atoms. :0: ***H O (1) trigonal pyramidal (2) bent (3) bent O (1) trigonal planar (2) bent (3) trigonal planar O (1) trigonal planar (2) tetrahedral (3) trigonal pyramidal O (1) trigonal pyramidal (2) tetrahedral (3) trigonal pyramidal
((11.4) Consider the molecule below. Determine the molecular geometry at each of the labelled atoms. :0: ***H O (1) trigonal pyramidal (2) bent (3) bent O (1) trigonal planar (2) bent (3) trigonal planar O (1) trigonal planar (2) tetrahedral (3) trigonal pyramidal O (1) trigonal pyramidal (2) tetrahedral (3) trigonal pyramidal
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:### Determining Molecular Geometry
**Question:** Consider the molecule below. Determine the molecular geometry at each of the labelled atoms.
**Molecule Diagram:**
The molecule consists of a Carbon (C) atom connected to:
- An Oxygen (O) atom via a double bond, shown with two sets of colons representing lone pairs on the oxygen.
- A Chlorine (Cl) atom with two sets of colons representing lone pairs on the chlorine.
- A Nitrogen (N) atom connected to two Hydrogen (H) atoms, with the nitrogen atom having a lone pair represented by a colon.
- A Hydrogen (H) atom directly bound to the central Carbon (C) atom.
The labeled atoms are:
1. Carbon (C) connected to Oxygen (O), Chlorine (Cl), and one Hydrogen (H).
2. Nitrogen (N) connected to two Hydrogen (H).
3. Oxygen (O) connected to Carbon (C).
**Choices:**
1. (1) trigonal pyramidal (2) bent (3) bent
2. (1) trigonal planar (2) bent (3) trigonal planar
3. (1) trigonal planar (2) tetrahedral (3) trigonal pyramidal
4. (1) trigonal pyramidal (2) tetrahedral (3) trigonal pyramidal
**Options Analysis:**
- **Option 1:** Suggests that the Carbon is trigonal pyramidal, Nitrogen is bent, and Oxygen is bent.
- **Option 2:** Indicates Carbon is trigonal planar, Nitrogen is bent, and Oxygen is trigonal planar.
- **Option 3:** Implies Carbon is trigonal planar, Nitrogen is tetrahedral, and Oxygen is trigonal pyramidal.
- **Option 4:** Positions Carbon as trigonal pyramidal, Nitrogen as tetrahedral, and Oxygen as trigonal pyramidal.
**Correct Answer:** The solution requires analyzing the electronic geometry and the molecular shapes based on the electron pairs around the central atoms.
---
**Note for Educational Website:**
The key to answering this question lies in understanding valence shell electron pair repulsion (VSEPR) theory, which can predict the shape of a molecule by considering repulsions between electron pairs around the central atom. By identifying the number of bonding and lone pairs on each central atom, the molecular geometry can be determined.
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