11.3 The ascending and descending gradient of a vertical curve is 1/40 and 1/50 respectively. Compute the minimum length of the curve for a design speed of 80 km/hr and rate of change of acceleration of 0.6 m/s.

11.3 The ascending and descending gradient of a vertical curve is 1/40 and 1/50 respectively. Compute the minimum length of the curve for a design speed of 80 km/hr and rate of change of acceleration of 0.6 m/s.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Design of pavements

Pavement is a structure that is made up of different layers such as sub-base course layer, base course layer, binder course, and a surface course formed with different materials such as gravel, above the subgrade soil constructed to act as a path or carriageway enabling the movement of vehicles. The surface of the pavement should possess characteristics such as adequate friction, light reflection, and drainage. The pavements are classified based on structural design into rigid pavements, flexible pavements, composite pavements, and unpaved pavements. The process of determining a suitable pavement type, its constituent layers, and its thickness is called pavement design.

Question

Highway Engineering

11.3 The ascending and descending gradient of a vertical curve is 1/40 and 1/50 respectively.
Compute the minimum length of the curve for a design speed of 80 km/hr and rate of change of
acceleration of 0.6 m/s.

Expert Solution

Step 10

Given:

Ascending gradient, n₁ = 1/40

Descending gradient, n₂ = 1/50

Design speed, V = 80 km/hr

Rate of change of acceleration, c = 0.6 m/s³

Step 2

The formula for the length of curve is given by,

Where,

N = deviation angle

The formula for deviation angle is given by,

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