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11.14 For the Scotch yoke mechanism shown, the acceleration of point A is defined by the relation a = -1.08 sin kt - 1.44 cos kt, where a and t are expressed in m/s² and seconds, respectively, and k = 3 rad/s. Knowing that x = 0.16 m and v = 0.36 m/s when t = 0, determine the velocity and position of point A when t = 0.5 s. THIS SIDE UP OO ***** DVD-R POC

11.14 For the Scotch yoke mechanism shown, the acceleration of point A is defined by the relation a = -1.08 sin kt - 1.44 cos kt, where a and t are expressed in m/s² and seconds, respectively, and k = 3 rad/s. Knowing that x = 0.16 m and v = 0.36 m/s when t = 0, determine the velocity and position of point A when t = 0.5 s. THIS SIDE UP OO ***** DVD-R POC

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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11.14

11.14 For the Scotch yoke mechanism shown, the acceleration of point A is defined by the relation a = -1.08 sin kt - 1.44 cos kt, where a and t are expressed in m/s² and seconds, respectively, and k = 3 rad/s. Knowing that x = 0.16 m and v = 0.36 m/s when t = 0, determine the velocity and position of point A when t = 0.5 s. B A THIS SIDE UP C D Fig. P11.13 and P11.14 OO ..... TES DVD-R POOH
Transcribed Image Text:11.14 For the Scotch yoke mechanism shown, the acceleration of point A is defined by the relation a = -1.08 sin kt - 1.44 cos kt, where a and t are expressed in m/s² and seconds, respectively, and k = 3 rad/s. Knowing that x = 0.16 m and v = 0.36 m/s when t = 0, determine the velocity and position of point A when t = 0.5 s. B A THIS SIDE UP C D Fig. P11.13 and P11.14 OO ..... TES DVD-R POOH
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