11.1 A continuous foundation is required in a soil where c' =10 kN/m², þ' = 26°, and y = 19.0 kN/m³. The depth ofthe footing will be 1.0 m. The dead load and the live loadare 600 kN/m and 400 kN/m, respectively. Determine therequired width for the foundation based on allowable stressdesign with FS = 3, using Eq. (6.10) and Table 6.1.1qu = c'N. + qNq +5¥BN,(6.10)2 TABLE 6.1 Terzaghi's Bearing Capacity Factors-Eqs. (6.17), (6.15), and (6.13)"N.N.N,"N.N.5.701.000.002627.0914.219.846.001.100.012729.2415.9011.606.301.220.042831.6117.8113.7036.621.350.062934.2419.9816.1846.971.490.103037.1622.4619.1357.341.640.143140.4125.2822.656.7.731.810.203244.0428.5226.8778.152.000.273348.0932.2331.948.8.602.210.353452.6436.5038.049.092.440.443557.7541.4445.41109.612.690.563663.5347.1654.361110.162.980.693770.0153.8065.271210.763.290.853877.5061.5578.611311.413.631.043985.9770.6195.031412.114.021.264095.6681.27115.311512.864.451.5241106.8193.85140.511613.684.921.8242119.67108.75171.991714.605.452.1843134.58126.50211.561815.126.042.5944151.95147.74261.601916.566.703.0745172.28173.28325.342017.697.443.6446196.22204.19407.112118.928.264.3147224.55241.80512.842220.279.195.0948258.28287.85650.672321.7510.236.0049298.71344.63831.992423.3611.407.0850347.50415.141072.802525.1312.728.34

The given data is as follows: c'=10 kN/m2ϕ'=26∘γ=19.0 kN/m3Depth of footing=1.0 mDead load=600…

11.1 A continuous foundation is required in a soil where c' 10 kN/m², þ' = 26°, and y = 19.0 kN/m³. The depth of the footing will be 1.0 m. The dead load and the live load are 600 kN/m and 400 kN/m, respectively. Determine the required width for the foundation based on allowable stress design with FS = 3, using Eq. (6.10) and Table 6.1. 1 qu = c'N. + qN, + yBN, (6.10)

11.1 A continuous foundation is required in a soil where c' 10 kN/m², þ' = 26°, and y = 19.0 kN/m³. The depth of the footing will be 1.0 m. The dead load and the live load are 600 kN/m and 400 kN/m, respectively. Determine the required width for the foundation based on allowable stress design with FS = 3, using Eq. (6.10) and Table 6.1. 1 qu = c'N. + qN, + yBN, (6.10)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Question attached

Q: Question Attached

A: Gross bearing pressure: Gross bearing pressure is a total pressure at the base of the foundation due…

Q: determine the net increase in stress (kPa) at a depth of 1.3 m below the footing. Provide your…

A: Given:- Depth of the excavation = 1.17 m Unit weight of the soil removed =…

Q: QUESTION #2 A rectangular foundation (B x 1.2B) has to be constructed as shown in Figure. Assume…

Q: It is planned to construct a rectangular foundation with base dimensions of 8 * 14 m (B* L) on the…

Q: Allowable soil bearing capacity, qall (in kN/m2) if factor of safety is 3.0 qall = d. Total…

A: A shallow foundation is given in the question which has cohesion of 10KN/m2, internal friction of 36…

Q: Question attached

A: The maximum capacity of the pile depends on the superstructure load and the subgrade soil bearing…

Q: A strip foundation with dimensions B has to be constructed on sandy soil. The foundation will be…

A: Depending on the mechanism from which the deep foundation derives its bearing capacity, its shape…

Q: A rectangular footing foundation with dimensions of 1.5 m x 1.5 m is located at a depth of Df = 0.5…

A: Bearing capacity : Bearing capacity refers to a soil's ability to withstand forces applied to it.…

Q: of safety is 3. Using Terzaghi's Bearing capacity equation, determine the design load on the…

A: Give data A=1.5m×1.5m Friction angle, ϕ=28o C=15.2kPa unit weight=19.8kN/m3

Q: A square foundation must withstand an allowable load of 1805 kN with reliability of 3. With the…

Q: A footing with 2x5 m is founded at a depth of 1 m in a stiff clay of saturated unit weight 19 kN/m³,…

A: Saturated unit weight= 19 KN/m3 Depth of footing= 1 m Su= 105 Kpa Footing = 2*5 m

Q: 2 ft 24 ft 24 ft 24 ft 2 ft Problem 4 B E F G 3 ft DL=190 kip DL-100 kip DL=180 kip LL = 60 kip LL=…

A: Given data: Size of the mat = 76 ft by 96 ft Column size = 24 in. by 24 in. qall(net)=1.5 kip/ft2…

Q: A square foundation is placed at a depth of 1.5 m within a sandy clay where c'=14k/m2 , phi'=23 and…

A: Compaction is the process in which soil gets distributed properly and its quantity gets pressured by…

Q: 9.3 Given: T-shape foundation as shown in figure is loaded with a uniform load of 120 kN/m².…

A: T shaped foundation loaded with uniform load q = 120 kPa

Q: What is the ultimate bearing capacity, if it is a strip footing? y = 16 kN/m c' =0 d' = 32° 0.5 m…

A: Solution:- Ultimate bearing capacity of Strip footing generally is given as: qu=cNc+γDfNq+0.5γBNγ…

Q: A long foundation 0.6 m wide carries a line load of 100 kN/m. Calculate the vertical stress, at a…

A: Given: The width of the foundation is 0.6 m. The line load is 100 kN/m. The coordinate x is 2.75 m.…

Q: A column foundation is 3 m × 2 m in plan. Given: Df = 1.5 m, ' = 30°, c' = 80 kN/m². Using the…

A: Foundation: L = 3m B = 2 m Depth of the footing, Df = 1.5 m The angle of internal friction, ϕ=30o…

Q: 2. A medium dense sand is proposed to support a square foundation having a width and length of 5…

A: Consider the free body diagram as;

Q: Refer to Figure 5.9. For a continuous foundation in two-layered clay, given:●● γ1 = 121 lb/ft3,…

Q: Refer to Figure 5.2. Given: B = L = 1.75 m, Df = 1 m, H = 1.75 m, γ = 17 kN/m3, c' = 0, and Φ' =…

A: The general bearing capacity equation as modified by Cerato and Lutenegger (2006) for square…

Q: A foundation is to be constructed at a site where the soil profile is as shown bel dimensions of…

A: a.) calculate the initial pressure at mid-height of clay layer…

Q: 3. A column foundation (Figure 1) is 3 m x 2 m in plane. Given: D;= 2m, o=25°, c = 50 kN/m². Using…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Problem # 2 A square footing (8 ft x 8 ft) supports a square column 14 in x 14 in. The column and…

Q: A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC)…

A: Given data load = 500 KN Foundation is square that means Same dimensions Depth of foundation= 2m…

Q: A rectangular footing 1.64 x 2.31 meters in plan. The soil supporting the foundation has a friction…

Q: The square foundation with 2.0 m width was built close to the slope and causes an increase in…

A: depth of the beam is not given Assume depth of the foundation H=2.0 mcohesion for the soil C=0 and…

Q: Y-17 kN/m d-36° c'-10 kN/m? Df=1.5m B=1.25m The above figure shows a square footing. The properties…

Q: Refer to Figure 5.2 and consider a rectangular foundation. Given: B = 1.5 m, L = 2.5 m, Df = 1.2 m,…

A: Solution Given Data B = 1.5 m, L = 2.5 m, Df = 1.2 m, H = 0.9 m, Φ' = 40º, c' = 0, and γ = 17 kN/m3.…

Q: Q. No. 1: A foundation 4x4 m is located at a depth of 1 m in a layer of saturated clay 13 m thick.…

A: Solution Given Data Cu=1 kN/m2ϕu=0c'=0ϕ'=320Cc=0.36e0=0.784γsat=21 kN/m3

Q: Explain the problem attached

A: since type of shallow footing is not provided we assumed it to be strip footing Nc=5.7,Nq=1,Nϒ=0,…

Q: A footing with 2×5 m is founded at a depth of 1 m in a stiff clay of saturated unit weight 19 kN/m³,…

A: Saturated unit weight= 19 KN/m3 Depth of footing= 1 m

Q: b. Ultimate soil bearing capacity, qu (in kN/m2) qu = c. Allowable soil bearing capacity, qall (in…

A: γ = 17 Knm3ϕ = 36°c' = 10 KNm2Df = 1.5mB = 1.25m

Q: Question: A 600 kN column load is to be supported on a 1.5 m circular footing of a residential…

A: Column load = 600 kNDepth of footing(d) = 1.0 mHeight of soil layer (H) = 4.5 m silty sandUnit…

Q: A foundation is constructed in a soil with the following parameters: c' = 5.0kN/m? y = 18.5 kN/m³ Ø'…

A: The given data is: B=2 m L=3 m C'=5 KN/m2 Q=3000 KN M=300 KN-m calculating eccentricity:…

Q: 5.6 For a square foundation that is B X B in plan, D, = 2 m; ver- tical gross allowable load Qall…

A: square footing

Q: Problem Set 3 (PS3) P. Y-17 kN/m d-36° c'-10 kN/m? Df-1.5m B=1.25m The above figure shows a square…

Q: Repeat Problem 11.1 based on limit state design, using the factors given in Table 11.4. 11.1 A…

Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

11.1 A continuous foundation is required in a soil where c' =
10 kN/m², þ' = 26°, and y = 19.0 kN/m³. The depth of
the footing will be 1.0 m. The dead load and the live load
are 600 kN/m and 400 kN/m, respectively. Determine the
required width for the foundation based on allowable stress
design with FS = 3, using Eq. (6.10) and Table 6.1.
1
qu = c'N. + qNq +5¥BN,
(6.10)
2

TABLE 6.1 Terzaghi's Bearing Capacity Factors-Eqs. (6.17), (6.15), and (6.13)"
N.
N.
N,"
N.
N.
5.70
1.00
0.00
26
27.09
14.21
9.84
6.00
1.10
0.01
27
29.24
15.90
11.60
6.30
1.22
0.04
28
31.61
17.81
13.70
3
6.62
1.35
0.06
29
34.24
19.98
16.18
4
6.97
1.49
0.10
30
37.16
22.46
19.13
5
7.34
1.64
0.14
31
40.41
25.28
22.65
6.
7.73
1.81
0.20
32
44.04
28.52
26.87
7
8.15
2.00
0.27
33
48.09
32.23
31.94
8.
8.60
2.21
0.35
34
52.64
36.50
38.04
9.09
2.44
0.44
35
57.75
41.44
45.41
10
9.61
2.69
0.56
36
63.53
47.16
54.36
11
10.16
2.98
0.69
37
70.01
53.80
65.27
12
10.76
3.29
0.85
38
77.50
61.55
78.61
13
11.41
3.63
1.04
39
85.97
70.61
95.03
14
12.11
4.02
1.26
40
95.66
81.27
115.31
15
12.86
4.45
1.52
41
106.81
93.85
140.51
16
13.68
4.92
1.82
42
119.67
108.75
171.99
17
14.60
5.45
2.18
43
134.58
126.50
211.56
18
15.12
6.04
2.59
44
151.95
147.74
261.60
19
16.56
6.70
3.07
45
172.28
173.28
325.34
20
17.69
7.44
3.64
46
196.22
204.19
407.11
21
18.92
8.26
4.31
47
224.55
241.80
512.84
22
20.27
9.19
5.09
48
258.28
287.85
650.67
23
21.75
10.23
6.00
49
298.71
344.63
831.99
24
23.36
11.40
7.08
50
347.50
415.14
1072.80
25
25.13
12.72
8.34

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step 5

Step 6

Step 7

Step 8

Step 9

Step 10

Trending now

This is a popular solution!

Step by step

Solved in 10 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Please correct answer
answer in complete solution pls
1)
绘图编辑 3.12 For a strip foundation, the width is 1.2m, buried depth is 1.2m, the standard value of the load applied on the foundation F=155KN/m, the soil layer is distributed as follows: from the ground to the depth of 1.2m is the land fill, =18KN/m³; the depth in the range of 1.2~1.8m is silty clay, fak=155kPa, E,=8.1Mpa, y=19KN/m³; below the depth of 1.8m is the mucky clay, fak=102kPa, E,=2.7Mpa. Try to check the base pressure and the bearing capacity of the weak sub-layer. Ground F=155KN/m OLand fill 18KN/m³ 1.2m O Silty clay La-155kPa;E-8.1Mpa;y-19KN/m³ -0, 1.0 O Mucky clay -0, H1.0 Sak-102kPa;E,-2.7Mpa 1.2m
Please allow for all steps
A 1.70 m by 2.60 m footing has its base 1.70 m below the ground surface. GWT is a meter above its base. (L along x-axis) Y = 15.75 kN/m C= 15 kPa Yut = 19 kN/m =26° Using Meyerhof's formula, determine the net ultimate load that the footing could carry if e = 0.45 m and es = 0.30 m. PLEASE MAKE YOUR HANDWRITING READABLE AND CLEAR. THANK YOU SO MUCH :)
Use Terzaghi's equation and Terzaghi's Table
Calculate the ultimate bearing capacity of a 2 m wide strip foundation embedded 2 m below the ground surface in soil with a saturated unit weight of 20 kN/m3. Dry unit weight of 18&N /m The water table is at the foundation level. The friction angle is 30°. 1. Calculate the bearing capacity of the foundation. 2. The design load on the foundation is 500 kPa. Comment on the safety of the foundation.
Use Terzaghi equation and Terzaghi table.
plz answer asap