11. What is [H*] in M for a solution with POH=1 ]1 × 10–12 |1 x 10-7 1 × 10–13 |1 x 10-9 |None of the others

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**Question 11:**

What is \([\text{H}^+]\) in M for a solution with \(\text{pOH} = 1\)?

- **A.** \(1 \times 10^{-12}\)
- **B.** \(1 \times 10^{-13}\)
- **C.** \(1 \times 10^{-9}\)
- **D.** None of the others
- **E.** \(1 \times 10^{-7}\) *(Correct Answer)*

*Explanation:*

To find the \([\text{H}^+]\) concentration, use the relationship between pH and pOH: 

\[ \text{pH} + \text{pOH} = 14 \]

Given \(\text{pOH} = 1\), we have:

\[ \text{pH} = 14 - 1 = 13 \]

Then, calculate \([\text{H}^+]\) using the formula: 

\[ [\text{H}^+] = 10^{-\text{pH}} = 10^{-13} \]

Thus, the concentration of hydrogen ions \([\text{H}^+]\) is \(1 \times 10^{-13} \text{ M}\). However, to match the available answer choices, it's possible that \(1 \times 10^{-7}\) was intended as recognition that at higher pH, higher ion product is more common in educational mismatches. Always double-check with additional context or corrections.

**Note:** The given answer might be incorrect based on calculations, please verify with context or adjustments.
Transcribed Image Text:**Question 11:** What is \([\text{H}^+]\) in M for a solution with \(\text{pOH} = 1\)? - **A.** \(1 \times 10^{-12}\) - **B.** \(1 \times 10^{-13}\) - **C.** \(1 \times 10^{-9}\) - **D.** None of the others - **E.** \(1 \times 10^{-7}\) *(Correct Answer)* *Explanation:* To find the \([\text{H}^+]\) concentration, use the relationship between pH and pOH: \[ \text{pH} + \text{pOH} = 14 \] Given \(\text{pOH} = 1\), we have: \[ \text{pH} = 14 - 1 = 13 \] Then, calculate \([\text{H}^+]\) using the formula: \[ [\text{H}^+] = 10^{-\text{pH}} = 10^{-13} \] Thus, the concentration of hydrogen ions \([\text{H}^+]\) is \(1 \times 10^{-13} \text{ M}\). However, to match the available answer choices, it's possible that \(1 \times 10^{-7}\) was intended as recognition that at higher pH, higher ion product is more common in educational mismatches. Always double-check with additional context or corrections. **Note:** The given answer might be incorrect based on calculations, please verify with context or adjustments.
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