11. Two disks are cut from the same uniform board. The radius of disk B is twice the radius of the disk A. The disks can rotate around axes with negli- gible friction. Two very light battery-powered fans are attached to the disks, as shown in Figure Q9.11. When switched on, the fans exert equal forces on the disks. Which of the following correctly compares and explains the rotational accelerations of the disks after the fans are switched on? (a) aa = 4ag because Fg = F, and mg = 4ma. (b) aa = ag because Tg = 27A and Ig = 21A. 2ag because Tg = 27A and Ig = 41A. 4ag because Tg = 27A and Ig = 81A- Sag because Tg = 2TA and Ig = 16/A. (c) aA = %3! (d) aA %3D (e) aA = IGURE Q9.11 2r в

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11. Two disks are cut from the same uniform board. The radius of disk B is
twice the radius of the disk A. The disks can rotate around axes with negli-
gible friction. Two very light battery-powered fans are attached to the disks,
as shown in Figure Q9.11. When switched on, the fans exert equal forces
on the disks. Which of the following correctly compares and explains the
rotational accelerations of the disks after the fans are switched on?
(a) aa =
4ag because Fg = F, and mg = 4ma.
(b) aa = ag because Tg = 27A and Ig = 21A.
(c) aa =
%3D
2ag because 7g = 27A and Ig = 41A.
4ag because Tg = 27A and Ig = 814.
(d) aA =
(e) aa = 8ag because Tg = 27A and Ig = 16/Ą.
%3D
FIGURE Q9.11
2r
B
Transcribed Image Text:11. Two disks are cut from the same uniform board. The radius of disk B is twice the radius of the disk A. The disks can rotate around axes with negli- gible friction. Two very light battery-powered fans are attached to the disks, as shown in Figure Q9.11. When switched on, the fans exert equal forces on the disks. Which of the following correctly compares and explains the rotational accelerations of the disks after the fans are switched on? (a) aa = 4ag because Fg = F, and mg = 4ma. (b) aa = ag because Tg = 27A and Ig = 21A. (c) aa = %3D 2ag because 7g = 27A and Ig = 41A. 4ag because Tg = 27A and Ig = 814. (d) aA = (e) aa = 8ag because Tg = 27A and Ig = 16/Ą. %3D FIGURE Q9.11 2r B
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