11. Steady-state creep data taken for an iron at a stress level of 140 MPa (20,000 psi) are given here: T (K) 6.6 × 10 * 1090 8.8 × 10 ? 1200 If it is known that the value of the stress exponent n for this alloy is 8.5, compute the steady-state creep rate at 1300 K and a stress level of 83 MPa (12,000 psi).

Introduction to Chemical Engineering Thermodynamics
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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**11. Steady-State Creep Data for Iron**

Steady-state creep data taken for an iron at a stress level of 140 MPa (20,000 psi) are given here:

\[
\begin{array}{|c|c|}
\hline
\dot{\varepsilon}_s \, (\text{h}^{-1}) & T \, (\text{K}) \\
\hline
6.6 \times 10^{-4} & 1090 \\
8.8 \times 10^{-2} & 1200 \\
\hline
\end{array}
\]

*Task:* If it is known that the value of the stress exponent \( n \) for this alloy is 8.5, compute the steady-state creep rate at 1300 K and a stress level of 83 MPa (12,000 psi).
Transcribed Image Text:**11. Steady-State Creep Data for Iron** Steady-state creep data taken for an iron at a stress level of 140 MPa (20,000 psi) are given here: \[ \begin{array}{|c|c|} \hline \dot{\varepsilon}_s \, (\text{h}^{-1}) & T \, (\text{K}) \\ \hline 6.6 \times 10^{-4} & 1090 \\ 8.8 \times 10^{-2} & 1200 \\ \hline \end{array} \] *Task:* If it is known that the value of the stress exponent \( n \) for this alloy is 8.5, compute the steady-state creep rate at 1300 K and a stress level of 83 MPa (12,000 psi).
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