11.K, (NH,) = 10 5)(A)-0.44 VFor the cell,Pt(s) | H₂(0.5 bar) | HCI (0.01M) | AgCl(s) | Ag(s)E = 0.22V at 25°C. Ecell at 25°C is (log20.30)(A) 0.0V(B) 0.45 V(C) 0.67 V(B)-0.88 VSpage for(C)-0.22 V=W(D)-0.11 V(D) -0.23 V

In this question, we have to determine the cell potential from the given value of E°cell which is…

11. *, K, (NH,) = 105) (B)-0.88 V (A))-0.44 V For the cell, Pt(s) | H₂(0.5 bar) | HC1 (0.01M) | AgCl(s) | Ag(s) cell E = 0.22V at 25°C. E at 25°C is (log2 = 0.30) (A) 0.0V (B) 0.45 V (C) 0.67 V (C)-0.22 V Snago for R (D)-0.11 V (D) -0.23 V

11. *, K, (NH,) = 105) (B)-0.88 V (A))-0.44 V For the cell, Pt(s) | H₂(0.5 bar) | HC1 (0.01M) | AgCl(s) | Ag(s) cell E = 0.22V at 25°C. E at 25°C is (log2 = 0.30) (A) 0.0V (B) 0.45 V (C) 0.67 V (C)-0.22 V Snago for R (D)-0.11 V (D) -0.23 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

11.
K, (NH,) = 10 5)
(A)-0.44 V
For the cell,
Pt(s) | H₂(0.5 bar) | HCI (0.01M) | AgCl(s) | Ag(s)
E = 0.22V at 25°C. Ecell at 25°C is (log2
0.30)
(A) 0.0V
(B) 0.45 V
(C) 0.67 V
(B)-0.88 V
Spage for
(C)-0.22 V
=
W
(D)-0.11 V
(D) -0.23 V

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