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11. How many mL of a 1.35 M solution will contain 8.20 mole NaOH? 8.20 mole -6.074L 1.35m 6070 mL 6070 m² = 85.23 859

11. How many mL of a 1.35 M solution will contain 8.20 mole NaOH? 8.20 mole -6.074L 1.35m 6070 mL 6070 m² = 85.23 859

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need help with my homework. Can you help me number 11 question, please?

M₁ V₁ = M₁ V₂ V₂ = M₁ V₁ ma 9. What volume of a 5.0 M solution is needed to make 1.5 L of 2.0M NaOH? V₂ = 20m x 1.5L = 0.60L .60 L 5.0m 10. Calculate the number of moles and the number of grams of solute in 2.0L of a 0.30 M Na₂SO4 solution. molez molarity X volume tu Kya.or= પડ૧૬ S1X3267= 32.07 04/16.00 = 42.05g/mdl .60 moles= 85g 6070 mL m, : 2.0m Vi: 1.5L 11. How many mL of a 1.35 M solution will contain 8.20 mole NaOH? 8.20 mole = 6.074L 1.35m 0.30m x 2.0L = 0.60 moles m2:5.0m 0.60 mol X142.05g/mol = 85.23 ૨૬૩ 6070 m²
Transcribed Image Text:M₁ V₁ = M₁ V₂ V₂ = M₁ V₁ ma 9. What volume of a 5.0 M solution is needed to make 1.5 L of 2.0M NaOH? V₂ = 20m x 1.5L = 0.60L .60 L 5.0m 10. Calculate the number of moles and the number of grams of solute in 2.0L of a 0.30 M Na₂SO4 solution. molez molarity X volume tu Kya.or= પડ૧૬ S1X3267= 32.07 04/16.00 = 42.05g/mdl .60 moles= 85g 6070 mL m, : 2.0m Vi: 1.5L 11. How many mL of a 1.35 M solution will contain 8.20 mole NaOH? 8.20 mole = 6.074L 1.35m 0.30m x 2.0L = 0.60 moles m2:5.0m 0.60 mol X142.05g/mol = 85.23 ૨૬૩ 6070 m²
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