**Problem Statement: Memory Alignment and Structs**Following is a definition of a `widget` and a declaration of an array `A` that contains 10 `widgets`. The sizes of a `byte`, `short`, `int`, and `long` are 1, 2, 4, and 8 bytes, respectively. Alignment is restricted so that an n-byte field must be located at an address divisible by n. The fields in a `struct` are not rearranged; padding is used to ensure alignment. All `widgets` in `A` must have the same size.```cstruct widget short s byte b long l int iend widgetwidget A[10]```**Question:**Assuming that `A` is located at a memory address divisible by 8, what is the total size of `A`, in bytes?**Explanation:**To calculate the total size of `A`, each `widget` must be aligned correctly:1. **`short s` (2 bytes):** Requires alignment on a 2-byte boundary.2. **`byte b` (1 byte):** Follows directly after `short`, adding 1 byte.3. **`long l` (8 bytes):** Needs alignment on an 8-byte boundary, likely introducing padding if the current offset isn't a multiple of 8.4. **`int i` (4 bytes):** Needs alignment on a 4-byte boundary.Calculate the total size of one `widget` by summing the space used by each field, including any padding for alignment. This is then multiplied by 10, as there are 10 `widgets` in the array `A`. If `A`'s start address is a multiple of 8, no additional alignment padding is needed.

Answered: 11. Following is adefinition of a…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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