11. Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle 45° with respect to the door at a distance of 0.5 m from the hinge then what is the value of the applied torque?

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle of 45° with respect to the door at a distance of 0.5 m from the hinge, then what is the value of the applied torque?

**Explanation:**

In this problem, we are asked to calculate the torque applied to a door by a force. Torque (τ) is given by the equation:

\[ \tau = r \cdot F \cdot \sin(\theta) \]

Where:
- \(\tau\) is the torque,
- \(r\) is the distance from the hinge (0.5 m in this case),
- \(F\) is the magnitude of the force (100 N in this case), and
- \(\theta\) is the angle between the force and the direction of the lever arm (45° in this case).

We can use this formula to find the magnitude of the applied torque by substituting the given values and calculating the sine of 45°. 

**Calculation:**

1. \(\sin(45°) = \frac{\sqrt{2}}{2} \approx 0.707\)
2. Substitute the values into the torque equation:

\[ \tau = 0.5 \, \mathrm{m} \cdot 100 \, \mathrm{N} \cdot 0.707 \]

3. Calculate the result:

\[ \tau \approx 35.35 \, \mathrm{N \cdot m} \]

Therefore, the value of the applied torque is approximately 35.35 N·m.
Transcribed Image Text:**Problem Statement:** Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle of 45° with respect to the door at a distance of 0.5 m from the hinge, then what is the value of the applied torque? **Explanation:** In this problem, we are asked to calculate the torque applied to a door by a force. Torque (τ) is given by the equation: \[ \tau = r \cdot F \cdot \sin(\theta) \] Where: - \(\tau\) is the torque, - \(r\) is the distance from the hinge (0.5 m in this case), - \(F\) is the magnitude of the force (100 N in this case), and - \(\theta\) is the angle between the force and the direction of the lever arm (45° in this case). We can use this formula to find the magnitude of the applied torque by substituting the given values and calculating the sine of 45°. **Calculation:** 1. \(\sin(45°) = \frac{\sqrt{2}}{2} \approx 0.707\) 2. Substitute the values into the torque equation: \[ \tau = 0.5 \, \mathrm{m} \cdot 100 \, \mathrm{N} \cdot 0.707 \] 3. Calculate the result: \[ \tau \approx 35.35 \, \mathrm{N \cdot m} \] Therefore, the value of the applied torque is approximately 35.35 N·m.
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