11. Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle 45° with respect to the door at a distance of 0.5 m from the hinge then what is the value of the applied torque?
11. Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle 45° with respect to the door at a distance of 0.5 m from the hinge then what is the value of the applied torque?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle of 45° with respect to the door at a distance of 0.5 m from the hinge, then what is the value of the applied torque?
**Explanation:**
In this problem, we are asked to calculate the torque applied to a door by a force. Torque (τ) is given by the equation:
\[ \tau = r \cdot F \cdot \sin(\theta) \]
Where:
- \(\tau\) is the torque,
- \(r\) is the distance from the hinge (0.5 m in this case),
- \(F\) is the magnitude of the force (100 N in this case), and
- \(\theta\) is the angle between the force and the direction of the lever arm (45° in this case).
We can use this formula to find the magnitude of the applied torque by substituting the given values and calculating the sine of 45°.
**Calculation:**
1. \(\sin(45°) = \frac{\sqrt{2}}{2} \approx 0.707\)
2. Substitute the values into the torque equation:
\[ \tau = 0.5 \, \mathrm{m} \cdot 100 \, \mathrm{N} \cdot 0.707 \]
3. Calculate the result:
\[ \tau \approx 35.35 \, \mathrm{N \cdot m} \]
Therefore, the value of the applied torque is approximately 35.35 N·m.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe822ee96-b072-4314-a719-51b641a0dd5d%2F8d689d31-4815-4cad-bfa1-a3cf69dedd7a%2Fayj2xhy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Consider the last drawing shown above. If the force has a magnitude of 100 N and is applied at an angle of 45° with respect to the door at a distance of 0.5 m from the hinge, then what is the value of the applied torque?
**Explanation:**
In this problem, we are asked to calculate the torque applied to a door by a force. Torque (τ) is given by the equation:
\[ \tau = r \cdot F \cdot \sin(\theta) \]
Where:
- \(\tau\) is the torque,
- \(r\) is the distance from the hinge (0.5 m in this case),
- \(F\) is the magnitude of the force (100 N in this case), and
- \(\theta\) is the angle between the force and the direction of the lever arm (45° in this case).
We can use this formula to find the magnitude of the applied torque by substituting the given values and calculating the sine of 45°.
**Calculation:**
1. \(\sin(45°) = \frac{\sqrt{2}}{2} \approx 0.707\)
2. Substitute the values into the torque equation:
\[ \tau = 0.5 \, \mathrm{m} \cdot 100 \, \mathrm{N} \cdot 0.707 \]
3. Calculate the result:
\[ \tau \approx 35.35 \, \mathrm{N \cdot m} \]
Therefore, the value of the applied torque is approximately 35.35 N·m.
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