11. ACEF is a parallelogram; Given: AC = BC; 1= 22 21 Prove: ACEF is a rhombus statement reason 1. 1. Inamainte 2. 2. 3. 3. 4. 4. 5. 5. 6. 6. 7. 7. 8. 8. Choose from this list Opposite sides of a parallelogram are congruent Given 00 Given ACEF is a rhombus 21 L2 If base angles of a triangle are congruent, AC = BC i then triangle is isosceles EC = AC ACEF is a parallelogram Given ACEB is isosceles transitive EC = CB Definition of isosceles property EF = AC and FA EC |Definition of rhombus, all sides are congruent

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