11. A forest ranger needs to estimate the height of a sequoia tree in the forest. At one point, the angle of elevation to the top of the tree is 15°12'. The ranger walks forward 35 feet from this point toward the tree and remeasures the angle of elevation to be 25°. To the nearest foot, how tall is the tree? A complete solution must include a properly labelled diagram.

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Chapter1: Trigonometry
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### Problem 11:

A forest ranger needs to estimate the height of a sequoia tree in the forest. At one point, the angle of elevation to the top of the tree is \(15^\circ 12'\). The ranger walks forward 35 feet from this point toward the tree and remeasures the angle of elevation to be \(25^\circ\). To the nearest foot, how tall is the tree? A complete solution must include a properly labeled diagram.

**Solution Explanation:**

1. **Initial Setup:**
   - Let \( h \) be the height of the tree we need to find.
   - The ranger initially stands at point \( A \) and measures the angle of elevation \( \theta_1 = 15^\circ 12' \).
   - After walking 35 feet towards the tree, the ranger is at point \( B \) and measures a new angle of elevation \( \theta_2 = 25^\circ \).

2. **Forming Right Triangles:**
   - Let \( D \) be the base of the tree, directly below the top of the tree.
   - The distance \( AD = x \) and \( BD = x - 35 \).

3. **Using Trigonometric Ratios:**
   - From the first observation point \( A \):
     \[
     \tan(15^\circ 12') = \frac{h}{x}
     \]
   - From the second observation point \( B \):
     \[
     \tan(25^\circ) = \frac{h}{x - 35}
     \]

4. **Solving for \( h \):**
   - Calculate \( \tan(15^\circ 12') \approx 0.271 \) and \( \tan(25^\circ) \approx 0.466 \).
   - Set up the equations:
     \[
     h = x \cdot 0.271
     \]
     \[
     h = (x - 35) \cdot 0.466
     \]
   - Equate the two expressions for \( h \):
     \[
     x \cdot 0.271 = (x - 35) \cdot 0.466
     \]
     \[
     0.271x = 0.466x - 16.31
     \]
     \[
Transcribed Image Text:### Problem 11: A forest ranger needs to estimate the height of a sequoia tree in the forest. At one point, the angle of elevation to the top of the tree is \(15^\circ 12'\). The ranger walks forward 35 feet from this point toward the tree and remeasures the angle of elevation to be \(25^\circ\). To the nearest foot, how tall is the tree? A complete solution must include a properly labeled diagram. **Solution Explanation:** 1. **Initial Setup:** - Let \( h \) be the height of the tree we need to find. - The ranger initially stands at point \( A \) and measures the angle of elevation \( \theta_1 = 15^\circ 12' \). - After walking 35 feet towards the tree, the ranger is at point \( B \) and measures a new angle of elevation \( \theta_2 = 25^\circ \). 2. **Forming Right Triangles:** - Let \( D \) be the base of the tree, directly below the top of the tree. - The distance \( AD = x \) and \( BD = x - 35 \). 3. **Using Trigonometric Ratios:** - From the first observation point \( A \): \[ \tan(15^\circ 12') = \frac{h}{x} \] - From the second observation point \( B \): \[ \tan(25^\circ) = \frac{h}{x - 35} \] 4. **Solving for \( h \):** - Calculate \( \tan(15^\circ 12') \approx 0.271 \) and \( \tan(25^\circ) \approx 0.466 \). - Set up the equations: \[ h = x \cdot 0.271 \] \[ h = (x - 35) \cdot 0.466 \] - Equate the two expressions for \( h \): \[ x \cdot 0.271 = (x - 35) \cdot 0.466 \] \[ 0.271x = 0.466x - 16.31 \] \[
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