Q.12 Solve in notebook-Post the picture in LMSAPPLICATIONS11. A 22 O resistor and a 33 Q resistor are connected in series and are connected to a120 V power source.a. What is the equivalent resistance of the circuit?b. What is the current in the circuit?c. What is the potential difference across each resistor?12. Three resistors of 3.3 kQ, 4.7 kN, and 3.9 kN are connected in series across a12 V battery.a. What is the equivalent resistance?b. What is the current through the resistors?c. Find the total potential difference across the three resistors.13. CHALLENGE Select a resistor to be used as part of a voltage divider along with a1.2 kO resistor. The potential difference across the 1.2 kQ resistor is to be 2.2 V whenthe supply is 12 V.

11. solution- Given that, R1= 22 ohm R2= 33 ohm E= 120 v

11. A 22 O resistor and a 33 O resistor are connected in series and are connected to a 120 V power source. a. What is the equivalent resistance of the circuit? b. What is the current in the circuit? c. What is the potential difference across each resistor?

11. A 22 O resistor and a 33 O resistor are connected in series and are connected to a 120 V power source. a. What is the equivalent resistance of the circuit? b. What is the current in the circuit? c. What is the potential difference across each resistor?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: What is the cross product A x B? Find the x component. Find the y component.

Q: By finding the curl, determine if following force are conservative F = ix? + jy² + k z² 2 not…

A: Please see the next step for solution:-

Q: This time, V = 82.1 V; R1 = 78 Ohms; R2 = 161 Ohms; R3 = 97 Ohms; R4 = 112 Ohms; R5 = 82 Ohms; and…

Q: 12. Given the following points, what is resultant of the two forces: a 500N force directed along a…

Q: O Ä• (AxB) = ? A. 0 В. 1 C.AB D.A'B

A: In this problem, It is asking about the specify the question.

Q: Consider the vectors shown above. What is the cross product ? -180 m2 k 144 m2 k 103 m2 -103 m2 k…

Q: What is the magnitude of the cross product of the following vectors? A = -2i+ 3R B = 3j- 48 O 181 O…

Q: El sistema mostrado en la figura tiene un peso de 2177 N cuyo peso actua en el punto G mostrado en…

A: Ax = 712.965 NExplanation:

Q: Determine the magnitude of the force F = 300j parallel to the direction of AB? F= 300;N 3m

Q: This time, V = 93.7 V; R1 = 194 Ohms; R2 = 111 Ohms; R3 = 183 Ohms; R4 = 155 Ohms; R5 = 85 Ohms; and…

Q: . Which of the following statement(s) is/are correct? The angle between vector A and B is 90…

Q: This time, V = 61.4 V; R1 = 183 Ohms; R2 = 165 Ohms; R3 = 125 Ohms; R4 = 115 Ohms; R5 161 Ohms; and…

Q: 20. Sketch v + w and v – w for the vectors in Figure 23. FIGURE 23

A: The sum of the vector is,

Q: w=50kg cable 1=300N find cables 2 and 3 magnitudes for equilibrium

A: Find tension in cable 2 and cable 3

Q: From the given figure, determine the rectangular representation of the 500 N force. F = 500 N O a. F…

A: To solve this question we will use the concept of vector transformation. Let the angle between the…

Q: c. A. (F+ 2C) d. A. (2F+C) 2. Find the angle between the following pairs of vectors: a. A = -3.0 -…

Q: The direction of friction, O acts perpendicular to the surfaces in contact. acts in the same…

A: Frictional force resists the motion.

Q: The cross product of two identical vectors is a. 1 b. 180 c. 90 d. 0

A: Given in question - Two identical vectors. To find - Cross product of vectors. Solution - Step1 -…

Q: A (-3; 2; 0), B (0; D; 6), C (2; -3; 0) and D (0; -3; 0), Since FBA = 152, FBC= 201 and FBD 192,…

Q: g of 0.4 gear ratio. neter. The Motors a unce from station tw tion during accelen

A: Given: To find the accelerate mass of the system as,

Q: I understand I1 and I2, but what value is being used for I0?

A: Solution:Given:Student wants to know the value of I0 that appears in the definition of sound…

Q: 3. Determine the force in members GE, GC, BC E 1000 N 1m C 2m 2m 2m 3000 N

A: Let us consider: Now the equation of equilibrium can be written as: 1) ∑Fx-Ax=0Ax=1000 2)…

Q: 3. A = −1î - 2ĵ, B = 2î - 1ĵ, calculate the cross product of A x B.

A: Given, A = - 1i-2j B = 2 - 1j We need to calculate, A×B =?

Q: 6 Using torques, show whether the person can climb to 1/3 of the ladder and separately to the top of…

A: Given that: Mass of ladder, M=30 kgAngle with the floor, θ=55+25=80°Coefficient of friction,…

Q: For the two vectors shown on x-y axes in the figure, what is the cross product x ? O.17.2 m2 k O…

Q: The grid runs from -5 to 5 on both axes. Drawn on this grid are four vectors, labeled A⃗ A→ through…

A: Introduction: Vectors are the quantity which require both magnitude and direction for its…

Q: Find r(t) if r(t) = ti+ej + 4tet k and r(0) =i+j+ k. r(t)

Q: In the design of a control mechanism, it is determined that rod AB transmits a 390 N force P to the…

A: x component of a vector = A Cos θ

Q: The reaction (kips) at the right support of the following beam is most nearly: 5 kips/ft անու 8 ft…

A: The uniform distributed load is 5 kips/ft, the reaction force of this uniform distributed load is…

Q: Write down the Kirchhoff Junction equation and solve it for I, in terms of I2 and I3. Write the…

Q: B= 4.0 mT | = 2.6 A L=0.65 m Find the force on wire and direction for force?

A: Magnetic field (B) = 4 mT , into the pageCurrent (I) = 2.6 A , towards leftLength (L) = 0.65 m

Q: Determine the magnitude of the pin force at A. Assume W = 675 lb, a = 2.7 ft, b = 2.0 ft, r = 9 in.…

A: Moment about any point.

Q: Consider the gusset plate of a bridge truss shown in ( Figure 1). Suppose that F₁ = 8 kN. F₂ = 6 kN.…

Concept explainers

Instantaneous Power

Power is defined in physics as the amount of energy transmitted or transformed per unit time. The watt is the unit of electricity in the International System of Units, equivalent to one joule per second.

Question

Q.12

Solve in notebook-Post the picture in LMS
APPLICATIONS
11. A 22 O resistor and a 33 Q resistor are connected in series and are connected to a
120 V power source.
a. What is the equivalent resistance of the circuit?
b. What is the current in the circuit?
c. What is the potential difference across each resistor?
12. Three resistors of 3.3 kQ, 4.7 kN, and 3.9 kN are connected in series across a
12 V battery.
a. What is the equivalent resistance?
b. What is the current through the resistors?
c. Find the total potential difference across the three resistors.
13. CHALLENGE Select a resistor to be used as part of a voltage divider along with a
1.2 kO resistor. The potential difference across the 1.2 kQ resistor is to be 2.2 V when
the supply is 12 V.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

9c Qa О qb a/2 30 30 2 a/2 a R 90 a 90 a/2 a/2 6060 R R 30 r 30 30 90 90 30 a/2 a/2 a http://www.treenshop.com/Ireenshop/ArticlesPages/HiguresUninterest Article/The%20Equilateral%20 Triangle.htm qa = +1.8 nc, qb = -7.5 nC, qc = -8.7 nC, a = 30.0 cm The point charges are located at the corners of an equilateral triangle of side a. Determine the electric field at the center of the right side of the triangle. R || = r = 3 h 6 t
Two cables are tied together at C and are loaded as shown. Determine the tension in cable AC if W = 2321 N. Round off only on the final answer expressed in 3 decimals
A block of mass m = 1.34 kg (Block 1) at rest at Point A on an arc of smooth circular surface of radius L = 30 m. Another block of mass M = 3.22 kg (Block 2) is at the bottom of the arc as shown in Fig.6. The line between the center of the arc and Point A and the line between the center of the arc and Point B make an angle 0 = 35 deg. If Block 1 is released and slides on the arc and hits Block 2, Block 1 stops at Point B and Block 2 starts to move along the arc. What is the velocity of Block B right after the collision in m/s. Keep three significant figures for the answer. g= 9.80 m/s. There is no friction.
Since &o=8.85 x 10-12 C2/N-m², the units of E² can be reduced to O J s m O N s m J m 3 3 N m W m
This time, V = 69.5 V; R1 = 107 Ohms; R2 = 72 Ohms; R3 = 56 Ohms; R4 81 Ohms; R5 = 185 Ohms; and R6 = 62 Ohms. How much current flows through = resistor R4? 0.072A 0.103A 0.217A 0.320A
A 422 N was applied to a 273 kg block, find the normal force if the angle 0 = 66.1 degrees. F Select one: Oa 2849.0997 N Ob. 2507.1603 N Oc. 2292.3148 N Od 2678.1300 N
The system of knotted cords shown in the figure below supports the indicated weight. Compute for the forces on the two cables (AB and BC).
Given M = î + 5 j - 6 k and N = 2 î - 2 j - 3 k, calculate the vector product M × N. Î + +
Consider the two vectors A= 12i + 5j and B = -3i. What is the cross product Ax B? O51 k none of the answers -15k O 15 j 15 k O.51 k -21 O 21 k -51
| Joule = kg. S2
QUESTION 1 When you are swimming at the bottom of a pool, the water above and around you exerts force on your eardrunm. Calculate the force (in N) exerted on your eardrum when you are at the bottom of a pool that is 5.0 m deep. Assume that the area of your eardrum is 1 cm^2 and the density of water is 1000 kg/m^3 (10.000 cm^2 = 1m^2) (Ans: 5N) To solve this, which of the followving equation/s should you use (check as many that best applies) O du = dQ - dW or AU= Q - W O P= pgh 1 4192| F = 4περ O Q= MCAT F P= Op =m/V W = dv P2+pgh2+ O Tk= T+273.15K O F=ma O Fo=P fluiagV submerged O PV = nRT O F1 F2
Answer 1 only. Thanks.