11) In the forward reaction of this equilibrium, which substance acts as the Brønsted-Lowry base? H;S(aq) + CH;NH;(aq) = HS (aq) + CH3NH;"(aq) a) Both substances act as Brønsted-Lowry bases. b) Neither substance acts as a Brønsted-Lowry base. c) H2S(aq) d) CH;NH;(aq)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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**Question 11:**
In the forward reaction of this equilibrium, which substance acts as the Brønsted–Lowry base?

\[ \text{H}_2\text{S(aq)} + \text{CH}_3\text{NH}_2\text{(aq)} \rightleftharpoons \text{HS}^-\text{(aq)} + \text{CH}_3\text{NH}_3^+\text{(aq)} \]

Options:
a) Both substances act as Brønsted-Lowry bases.
b) Neither substance acts as a Brønsted-Lowry base.
c) \(\text{H}_2\text{S(aq)}\)
d) \(\text{CH}_3\text{NH}_2\text{(aq)}\)

**Explanation:**

This problem asks students to identify the Brønsted–Lowry base in the forward reaction of a given equilibrium. In a Brønsted–Lowry acid-base reaction, the base is the substance that accepts a proton (H⁺ ion). 

**Reaction Analysis:**
- \(\text{H}_2\text{S(aq)}\) donates a proton to \(\text{CH}_3\text{NH}_2\text{(aq)}\), forming \(\text{HS}^-\text{(aq)}\) and \(\text{CH}_3\text{NH}_3^+\text{(aq)}\).
- \(\text{CH}_3\text{NH}_2\text{(aq)}\) accepts a proton, and thus acts as the Brønsted-Lowry base.

Therefore, the correct answer is:

d) \(\text{CH}_3\text{NH}_2\text{(aq)}\)
Transcribed Image Text:**Question 11:** In the forward reaction of this equilibrium, which substance acts as the Brønsted–Lowry base? \[ \text{H}_2\text{S(aq)} + \text{CH}_3\text{NH}_2\text{(aq)} \rightleftharpoons \text{HS}^-\text{(aq)} + \text{CH}_3\text{NH}_3^+\text{(aq)} \] Options: a) Both substances act as Brønsted-Lowry bases. b) Neither substance acts as a Brønsted-Lowry base. c) \(\text{H}_2\text{S(aq)}\) d) \(\text{CH}_3\text{NH}_2\text{(aq)}\) **Explanation:** This problem asks students to identify the Brønsted–Lowry base in the forward reaction of a given equilibrium. In a Brønsted–Lowry acid-base reaction, the base is the substance that accepts a proton (H⁺ ion). **Reaction Analysis:** - \(\text{H}_2\text{S(aq)}\) donates a proton to \(\text{CH}_3\text{NH}_2\text{(aq)}\), forming \(\text{HS}^-\text{(aq)}\) and \(\text{CH}_3\text{NH}_3^+\text{(aq)}\). - \(\text{CH}_3\text{NH}_2\text{(aq)}\) accepts a proton, and thus acts as the Brønsted-Lowry base. Therefore, the correct answer is: d) \(\text{CH}_3\text{NH}_2\text{(aq)}\)
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