√11 (B) f()(0)=0 (C) the domain of f is [-1, 1] (D) the domain of f contains the interval (-√5, √√5) 5 Let f RR be a continuous 27-periodic function whose Fourier series is +00 cos(nx). Then the quadratic norm of f equals n=1 (A) T (B) 2π (C) √T (D) √2π 6 Let D = {(x, y) = R² : 0 ≤ y ≤ 3, - √9 - y² ≤ x ≤ √√3-y} and g : D continuous function. Then the integral f, g(x, y) dx dy equals 2+3 (A) (g(x,y) dy) dx + f (fo + g(x, y) dy) d dx
√11 (B) f()(0)=0 (C) the domain of f is [-1, 1] (D) the domain of f contains the interval (-√5, √√5) 5 Let f RR be a continuous 27-periodic function whose Fourier series is +00 cos(nx). Then the quadratic norm of f equals n=1 (A) T (B) 2π (C) √T (D) √2π 6 Let D = {(x, y) = R² : 0 ≤ y ≤ 3, - √9 - y² ≤ x ≤ √√3-y} and g : D continuous function. Then the integral f, g(x, y) dx dy equals 2+3 (A) (g(x,y) dy) dx + f (fo + g(x, y) dy) d dx
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 3E
Related questions
Question
The answer is C
Could you explain
![√11
(B) f()(0)=0
(C) the domain of f is [-1, 1]
(D) the domain of f contains the interval (-√5, √√5)
5 Let f RR be a continuous 27-periodic function whose Fourier series is
+00
cos(nx).
Then the quadratic norm of f equals
n=1
(A) T
(B) 2π
(C) √T
(D) √2π
6 Let D = {(x, y) = R² : 0 ≤ y ≤ 3, - √9 - y² ≤ x ≤ √√3-y} and g : D
continuous function. Then the integral f, g(x, y) dx dy equals
2+3
(A) (g(x,y) dy) dx + f (fo + g(x, y) dy) d
dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6099d21a-e15a-47f8-adbb-0c871c33581f%2Fd9ab4104-4d22-4634-aed3-1ca83c44171b%2F9mionuf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:√11
(B) f()(0)=0
(C) the domain of f is [-1, 1]
(D) the domain of f contains the interval (-√5, √√5)
5 Let f RR be a continuous 27-periodic function whose Fourier series is
+00
cos(nx).
Then the quadratic norm of f equals
n=1
(A) T
(B) 2π
(C) √T
(D) √2π
6 Let D = {(x, y) = R² : 0 ≤ y ≤ 3, - √9 - y² ≤ x ≤ √√3-y} and g : D
continuous function. Then the integral f, g(x, y) dx dy equals
2+3
(A) (g(x,y) dy) dx + f (fo + g(x, y) dy) d
dx
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