11) A brass rod is 69.5 cm long and an aluminum rod is 49.3 cm long when both rods are at an initial temperature of 0° C. The rods are placed in line with a gap of 1.2 cm between them, as shown in the figure. The distance between the far ends of the rods is maintained at 120.0 cm throughout. The temperature of both rods is raised equally until they are barely in contact. At what temperature does contact occur? The coefficients of linear expansion of brass and aluminum are 2.0 x10-5 K-1 (brass) and 2.4 x 10-5 K-1 (aluminum). -120.0 cm aluminum B) 420°C C) 510°C D) 470°C E) 440°C brass A) 490°C

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**Expansion of Brass and Aluminum Rods with Temperature Increase**

**Problem Statement:**

11) A brass rod is 69.5 cm long and an aluminum rod is 49.3 cm long when both rods are at an initial temperature of 0° C. The rods are placed in line with a gap of 1.2 cm between them, as shown in the figure. The distance between the far ends of the rods is maintained at 120.0 cm throughout. The temperature of both rods is raised equally until they are barely in contact. At what temperature does contact occur? The coefficients of linear expansion of brass and aluminum are 2.0 × 10⁻⁵ K⁻¹ (brass) and 2.4 × 10⁻⁵ K⁻¹ (aluminum).

The schematic diagram represents two rod segments (one of brass and one of aluminum) separated by a gap of 1.2 cm. The entire setup maintains a total length of 120.0 cm.

**Options:**

A) 490°C
B) 420°C
C) 510°C
D) 470°C
E) 440°C

**Explanation of Diagram:**

- **Brass rod**
  - Initial Length: 69.5 cm

- **Aluminum rod**
  - Initial Length: 49.3 cm

- **Total Distance Maintained:** 120.0 cm
- **Initial Gap Between Rods:** 1.2 cm

The purpose is to calculate the temperature at which the two rods, upon expanding due to the rise in temperature, will barely touch each other.

**Key Concepts:**

- **Linear Expansion Formula:**
  \[
  \Delta L = L_0 \alpha \Delta T
  \]
  where \( L_0 \) is the initial length, \( \alpha \) is the coefficient of linear expansion, and \( \Delta T \) is the change in temperature.

Given Data:
- \( \alpha_{brass} = 2.0 \times 10^{-5} \, \text{K}^{-1} \)
- \( \alpha_{aluminum} = 2.4 \times 10^{-5} \, \text{K}^{-1} \)

**Solution Approach:**

1. Calculate the individual expansions of brass and aluminum rods as they are heated.
2. Sum these
Transcribed Image Text:**Expansion of Brass and Aluminum Rods with Temperature Increase** **Problem Statement:** 11) A brass rod is 69.5 cm long and an aluminum rod is 49.3 cm long when both rods are at an initial temperature of 0° C. The rods are placed in line with a gap of 1.2 cm between them, as shown in the figure. The distance between the far ends of the rods is maintained at 120.0 cm throughout. The temperature of both rods is raised equally until they are barely in contact. At what temperature does contact occur? The coefficients of linear expansion of brass and aluminum are 2.0 × 10⁻⁵ K⁻¹ (brass) and 2.4 × 10⁻⁵ K⁻¹ (aluminum). The schematic diagram represents two rod segments (one of brass and one of aluminum) separated by a gap of 1.2 cm. The entire setup maintains a total length of 120.0 cm. **Options:** A) 490°C B) 420°C C) 510°C D) 470°C E) 440°C **Explanation of Diagram:** - **Brass rod** - Initial Length: 69.5 cm - **Aluminum rod** - Initial Length: 49.3 cm - **Total Distance Maintained:** 120.0 cm - **Initial Gap Between Rods:** 1.2 cm The purpose is to calculate the temperature at which the two rods, upon expanding due to the rise in temperature, will barely touch each other. **Key Concepts:** - **Linear Expansion Formula:** \[ \Delta L = L_0 \alpha \Delta T \] where \( L_0 \) is the initial length, \( \alpha \) is the coefficient of linear expansion, and \( \Delta T \) is the change in temperature. Given Data: - \( \alpha_{brass} = 2.0 \times 10^{-5} \, \text{K}^{-1} \) - \( \alpha_{aluminum} = 2.4 \times 10^{-5} \, \text{K}^{-1} \) **Solution Approach:** 1. Calculate the individual expansions of brass and aluminum rods as they are heated. 2. Sum these
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