11-12. The rapid sand filter being designed for Laramie has the characteristics shown below. Using the Rose equation, determine the headloss for the clean filter bed in a stratified condition. Depth = 0.75 m Filtration rate 230 m³/d- m² Sand specific gravity = 2.80 Shape factor 0.80 Stratified bed porosity = 0.50 Water temperature = 5°C 000 bozoq nom bod qoob as mat bnoosa oT and zzolbaod odi omuzzA .notiw over boy toda
11-12. The rapid sand filter being designed for Laramie has the characteristics shown below. Using the Rose equation, determine the headloss for the clean filter bed in a stratified condition. Depth = 0.75 m Filtration rate 230 m³/d- m² Sand specific gravity = 2.80 Shape factor 0.80 Stratified bed porosity = 0.50 Water temperature = 5°C 000 bozoq nom bod qoob as mat bnoosa oT and zzolbaod odi omuzzA .notiw over boy toda
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:11-12. The rapid sand filter being designed for Laramie has the characteristics shown below.
Using the Rose equation, determine the headloss for the clean filter bed in a stratified
condition.
Depth = 0.75 m
Filtration rate=230 m³/d. m²
Sand specific gravity = 2.80
Shape factor
= 0.80
Stratified bed porosity = 0.50
Water temperature = 5°C 000
Sand analysis
U.S. Standard
Sieve No.
8-12
12-16
16-20
20-30
30-40
40-50
50-70
Mass percent
retained
olas 19) misshpa palad.
thunde goed bi puntob bazog
Toli muibomonom bod qoob au
mis broosz orT 2007
reo azolbsod Isto odi of mat lait
lobodi omuzzA .notit ovar boy tooda
0.00
0.40
13.10
1.785
0.015
ee-q
54.50m od doinw 30 5i coltul sdı vilimsbl
30.20
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