10s 10s Let L be the inverse of the Laplace Transform of: s' + 8s – 9 s + 8s – 9 10s then, L s* + 8s – 9 |(c) e' -e -9t |(a) e' + 2e3 -9t (b) e' + e -9t -9t e -3t |(d) e' +9e- |(e) (f) le' + e' + 4 4 le

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A: Explanation of the answer is as follows

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Q: The inverse Laplace transform £¯¹{: L is equal to -3s +36 s²+36 *-^{- = − 3sin(6t)+6cos(6t). -3s +36…

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