What is the inverse Laplace transform of 4s/(s^2+16) - 36/(s^2+16)? 4s 36 s²+16 s²+16 4cos(4t) - 9sin(4t 4cos(4t) + 9sin(4t O 4cos(t) - 9sin(t) 9cos(9t) - 4sin(4t

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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What is the inverse Laplace transform of 4s/(s^2+16) - 36/(s^2+16)?
4s
36
s²+16 s²+16
4cos(4t) - 9sin(4t
4cos(4t) + 9sin(4t
O 4cos(t) - 9sin(t)
9cos(9t) - 4sin(4t
Transcribed Image Text:What is the inverse Laplace transform of 4s/(s^2+16) - 36/(s^2+16)? 4s 36 s²+16 s²+16 4cos(4t) - 9sin(4t 4cos(4t) + 9sin(4t O 4cos(t) - 9sin(t) 9cos(9t) - 4sin(4t
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