(10%) Problem 6: A battery (4V= 1.7 V) contains E = 1.7 kJ of energy. It is connected to a P = 5.5 W light bulb.> A 33% Part (a) Input an expression for the light bulb's resistance, R.Grade Summary0%100%R =DeductionsPotentialSubmissionsaΔΡ789 HOMEAttempts remaining: 3(3% per attempt)detailed viewAV46hi13kENDPVVo BACKSPACEDEL CLEARSubmitHintFeedbackI give up!Hints: 30% deduction per hint. Hints remaining: 2Feedback: 30% deduction per feedback.O A 33% Part (b) What is the resistance in 2?O A 33% Part (c) Assuming the voltage remains constant how long will the battery last in seconds?

(a) The expression for the resistance of the light bulb is, P=V2RR=∆V2P

Answered: (10%) Problem 6: A battery (4V= 1.7 V)…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter29: Direct Current (dc) Circuits

Section: Chapter Questions

Problem 19PQ

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