How to solve this question Part AIncorrect. Try Again 3Next >C09 AMre to search95%+ A O2/19/2021

Answered: 10electrons fiow thova…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Part A
Incorrect. Try Again 3
Next >
C09 AM
re to search
95%+ A O
2/19/2021

Expert Solution

given

N =1.5*10²⁰ electrons flow through across section of a ( d =3.6-mm) diameter iron wire in (t = 6.0 s)

The molar mass of iron m = 55.847 g/ mol

The density of iron ρ = 7.874 g / cm ³ at 20^oC.

The volume occupied by 1 mole ( V ) = molar mass / density

= (55.847 g/ mol) / (7.874 g / cm ³)

= 7.09 cm³

= 7.09 * 10 ^{- 6} m ³

^{Since the iron has 1 free electron
so, the number of free electron n =1 * N_A /V
= 6.023 * 10 23 electrons / ( 7.09 * 10 -6 m 3 )
=8.495 * 10 28 electrons / m3}

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