1071 – 12 + 2x3 -11 +1lr2 – 13 + 3x4 2x1 – x2 + 10x3 – 14 3r2 – 13 + 874 = 6 = 25 -11 15

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Consider the linear system

Use the Gauss-Jacobi method to find an approximation of the solution with precision e = 10−3 and initial approach (0 0 0 0)t

 

 
 
 
 
 
 
 
10r1 – 12 + 2x3
6
-x1 + 11x2 – x3 + 3x4
- x2 + 10x3 - x4
3x2 - x3 + 8x4
25
2x1 –
-11
15
Transcribed Image Text:10r1 – 12 + 2x3 6 -x1 + 11x2 – x3 + 3x4 - x2 + 10x3 - x4 3x2 - x3 + 8x4 25 2x1 – -11 15
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