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1001 0 110 1-1 Find a basis of the row space of A= by reducing A to reduced echelon form. 1012 2 0200-2J O2B= ((100 10].[0 130 1]) Ob.B= {(10 01 0).[110 1-1).[101 2 2]} OcB-{[10110),[0 100 -1).[00 10 2 )} Od. none of these Oe.B= ([100 10],[0 100 -1).[0 0 1 1 2 ]}

1001 0 110 1-1 Find a basis of the row space of A= by reducing A to reduced echelon form. 1012 2 0200-2J O2B= ((100 10].[0 130 1]) Ob.B= {(10 01 0).[110 1-1).[101 2 2]} OcB-{[10110),[0 100 -1).[00 10 2 )} Od. none of these Oe.B= ([100 10],[0 100 -1).[0 0 1 1 2 ]}

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1001 0 1 10 1-1 Find a basis of the row space of A= by reducing A to reduced echelon form. 1012 2 0 200-2] O2B= ((100 10].[0 13 0 1]) Ob.B= {[100 1 0).[1101-1).[10 1 2 2]} OcB={[10110),[0 10 0 -1).[00 10 2 )} Od. none of these Oe.B= ([100 10),[0 100 -1).[0 0 1 1 2 ]}
Transcribed Image Text:1001 0 1 10 1-1 Find a basis of the row space of A= by reducing A to reduced echelon form. 1012 2 0 200-2] O2B= ((100 10].[0 13 0 1]) Ob.B= {[100 1 0).[1101-1).[10 1 2 2]} OcB={[10110),[0 10 0 -1).[00 10 2 )} Od. none of these Oe.B= ([100 10),[0 100 -1).[0 0 1 1 2 ]}
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