**Section 10.5.3**Consider the hypothesis test \(H_0: \sigma^2_1 = \sigma^2_2\) against \(H_1: \sigma^2_1 < \sigma^2_2\). Suppose that the sample sizes are \(n_1 = 5\) and \(n_2 = 10\), and that \(s^2_1 = 23.2\) and \(s^2_2 = 28.8\). Use \(\alpha = 0.05\). Test the hypothesis and explain how the test could be conducted with a confidence interval on \(\sigma_1/\sigma_2\).

The question is about hypothesis testing and confidence interval.Given :No. of observations in the…

Answered: 10.5.3 Consider the hypothesis test Ho:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

a. What are the sample estimates of β0,β1,and β2? b. What is the least squares prediction equation? c. FindSSE,MSE,and standard deviation . Interpret the standard deviation in the context of the problem. d. Test H0: β1=0 against Ha: β1≠0.Use α=0.01. e. Use a 95% confidence interval to estimate β2. f. Find R2 and R^2_a and interpret these values. g. Find the test statistic for testing H0: β1=β2=0. h. Find the observed significance level of the test in part g.interpret the result.
A 95% confidence interval for u was given as -5.65 < u < 2.61. What would a test for Ho : µ = 0 vs H1 : µ # 0 conclude? A. reject the null hypothesis at a = 0.05 and all smaller a B. fail to reject the null hypothesis at a = = 0.05 and all smaller a C. reject the null hypothesis at a = 0.05 and all larger a D. fail to reject the null hypothesis at a = - 0.05 and all larger
Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distributions are relatively normal. Test Ho : HA = Ha VS H. : HA # Hg using the fact that Group A has 8 cases with a mean of 125 and a standard deviation of 18 while Group B has 15 cases with a mean of 118 and a standard deviation of 14. (a) Give the test statistic and thep-value. Round your answer for the test statistic to two decimal places and your answer for the p- value to three decimal places. test statistic = p-value = eTextbook and Media (b) What is the conclusion of the test? Test at a 10% level. O Reject Ho. O Do not reject Ho. eTextbook and Media
27. Bob selects independent random samples from two populations and obtains the values î1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: 0.200 + 1.96(0.048) = 0.200 ± 0.094. Note that 0.048 is called the estimated standard error of pi – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success rates: Pi +P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (p1 + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (Pi + P2)/2. Hint: The answer has our usual form: Pt. est. +1.96 × ESE of the estimate.
question 12.12 using the numbers from 12.11.
6.02 Consider X1,..., X100 iid. Obtain a 90% confidence interval for the mean response of X having observed ī = 3.5 and s² = 1.44.
17.34 (EX) Oligofructose and calcium absorption 1/6: Nondigestible oligosaccharides are known to stimulate calcium absorption in rats. A double-blind, randomized experiment investigated whether the consumption of oligofructose similarly stimulates calcium absorption in healthy male adolescents 14 to 16 years old. The subjects took a pill for nine days and had their calcium absorption tested on the last day. The experiment was repeated three weeks later. Some subjects received the oligofructose pill in the first round and then a pill containing sucrose (which served as a control). The order was switched for the remaining subjects. Here are the fractional calcium absorption data (in percent of intake) for 11 subjects: Subject Control 1 2 3 4 5 6 7 8 9 10 11 78.4 76.6 57.4 51.5 49.0 46.6 44.2 42.9 37.2 34.1 24.6 Oligofructose 62.0 95.1 46.5 49.4 89.7 43.8 50.3 51.6 66.6 52.7 54.0 Explain clearly why the matched pairs t test is the proper choice for this experimental design. O Because this…
6.05 Based on a random sample of size n = 40, the 95% confidence interval for the true mean weight in mg for beans of a certain type is (229.7,233.5). Obtain the 99% confidence interval.
A researcher reports t(22) = 5.30, p < .01 for an independent-measures experiment. How many individuals participated in the entire experiment? Question 15 options: 20 21 23 24
Is th're any solution?

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS

10.5.3 Consider the hypothesis test Ho: o = o against H₁: o < o2, respectively. Suppose that the sample sizes are n₁ = 5 and n₂ = 10, and that s² = 23.2 and s2 = 28.8. Use a = 0.05. Test the hypothesis and explain how the test could be conducted with a confidence interval on o,/0₂.