10. Identify the isomeric relationship between each pair of molecules below. The options are: ENANTIOMERS SAME MOLECULE CONSTITUTIONAL ISOMERS DIASTEREOMERS Please write your answer within the dotted lines for each set! CH₂CH3 Br CH3 Bran CH, CH₂ H H Br DA HO Br Br H 'Br Br CH3 CI Hiy HO Br CI NOT ISOMERS (3S,4R,5S)-trimethylnonane (3R,45,5S)-trimethylnonane (3S,4R,5S)-trimethylnonane (3S,4R,6S)-trimethylnonane (3S,4R,5S)-trimethyloctane (3S,4R,5S)-trimethylnonane

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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10. Identify the isomeric relationship between each pair of molecules below. The options are:
ENANTIOMERS
SAME MOLECULE
DIASTEREOMERS
CONSTITUTIONAL ISOMERS
Please write your answer within the dotted lines for each set!
CH3
Br
Br
Br
"Br
Bri
H
CH₂CH3
Br
CH₂CH3
HCH
Br CH3
Br
Home Ho
HO
CI
Hiy
HO
NOT ISOMERS
(3S,4R,5S)-trimethylnonane
(3R,4S,5S)-trimethylnonane
(3S,4R,5S)-trimethylnonane
(3S,4R,6S)-trimethylnonane
(3S,4R,5S)-trimethyloctane
(3S,4R,5S)-trimethylnonane
11. For the radical halogenation of (R)-3-methylhexane that we studied in Chapter 4,
are the major products chiral?
YES or
will the resulting product solution be optically active? YES or
Hint: it may help to draw out and consider the geometry & stereochemistry of the carbon-based radical intermediate
NO
NO
Transcribed Image Text:10. Identify the isomeric relationship between each pair of molecules below. The options are: ENANTIOMERS SAME MOLECULE DIASTEREOMERS CONSTITUTIONAL ISOMERS Please write your answer within the dotted lines for each set! CH3 Br Br Br "Br Bri H CH₂CH3 Br CH₂CH3 HCH Br CH3 Br Home Ho HO CI Hiy HO NOT ISOMERS (3S,4R,5S)-trimethylnonane (3R,4S,5S)-trimethylnonane (3S,4R,5S)-trimethylnonane (3S,4R,6S)-trimethylnonane (3S,4R,5S)-trimethyloctane (3S,4R,5S)-trimethylnonane 11. For the radical halogenation of (R)-3-methylhexane that we studied in Chapter 4, are the major products chiral? YES or will the resulting product solution be optically active? YES or Hint: it may help to draw out and consider the geometry & stereochemistry of the carbon-based radical intermediate NO NO
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