10). Consider this reaction: 2NH3(g) → N2(g) + 3H2(g) If the rate A[H2]/At is 0.030 M-1.s-1, then A[NH3]/At is

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**Question 10: Reaction Rate Calculation**

Consider the chemical reaction:
\[ 2\text{NH}_3(\text{g}) \rightarrow \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \]

If the rate of change of the concentration of hydrogen gas (\(\Delta[\text{H}_2]/\Delta t\)) is \(0.030 \, \text{M} \cdot \text{s}^{-1}\), determine the rate of change of the concentration of ammonia (\(\Delta[\text{NH}_3]/\Delta t\)).

To solve this, use the stoichiometric relationships from the balanced chemical equation. The relationship between the rates for each component can be derived from the coefficients:
\[ \text{Rate of } \text{H}_2 = 3 \times \text{Rate of NH}_3 \]

Thus, knowing the rate of formation of \(\text{H}_2\), the rate of disappearance of \(\text{NH}_3\) can be calculated as:
\[ \Delta[\text{NH}_3]/\Delta t = \text{Rate of } \text{H}_2 / 3 \]

\[ \Delta[\text{NH}_3]/\Delta t = 0.030 \, \text{M} \cdot \text{s}^{-1} / 3 \]
\[ \Delta[\text{NH}_3]/\Delta t = 0.010 \, \text{M} \cdot \text{s}^{-1} \]

Therefore, the rate of change of concentration of ammonia (\(\Delta[\text{NH}_3]/\Delta t\)) is \(0.010 \, \text{M} \cdot \text{s}^{-1}\).
Transcribed Image Text:**Question 10: Reaction Rate Calculation** Consider the chemical reaction: \[ 2\text{NH}_3(\text{g}) \rightarrow \text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \] If the rate of change of the concentration of hydrogen gas (\(\Delta[\text{H}_2]/\Delta t\)) is \(0.030 \, \text{M} \cdot \text{s}^{-1}\), determine the rate of change of the concentration of ammonia (\(\Delta[\text{NH}_3]/\Delta t\)). To solve this, use the stoichiometric relationships from the balanced chemical equation. The relationship between the rates for each component can be derived from the coefficients: \[ \text{Rate of } \text{H}_2 = 3 \times \text{Rate of NH}_3 \] Thus, knowing the rate of formation of \(\text{H}_2\), the rate of disappearance of \(\text{NH}_3\) can be calculated as: \[ \Delta[\text{NH}_3]/\Delta t = \text{Rate of } \text{H}_2 / 3 \] \[ \Delta[\text{NH}_3]/\Delta t = 0.030 \, \text{M} \cdot \text{s}^{-1} / 3 \] \[ \Delta[\text{NH}_3]/\Delta t = 0.010 \, \text{M} \cdot \text{s}^{-1} \] Therefore, the rate of change of concentration of ammonia (\(\Delta[\text{NH}_3]/\Delta t\)) is \(0.010 \, \text{M} \cdot \text{s}^{-1}\).
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