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10. Consider the battery below containing IM CuSO4 and 1MZnSO4 which is capable delivering a voltage of 1.104 V. You need this voltage to operate your device. Eventually the battery will stop functioning as the voltage will drops to near zero. What can you do to extend the lifetime of the battery. 50, 2 Na 0.76 V Salt bridge Cu²+26 Cu(s) +0.34 V Cu Zn(s) SO, 2² SO, Zinc (anode) Zn(s)- Zn²+20 +0.76 V Zn²+ Cu(s) a. Modify your device to operate at a lower voltage. b. Increase the concentration of CuSO4 in the electrolyte. c. Increase the size of the Zn anode.

10. Consider the battery below containing IM CuSO4 and 1MZnSO4 which is capable delivering a voltage of 1.104 V. You need this voltage to operate your device. Eventually the battery will stop functioning as the voltage will drops to near zero. What can you do to extend the lifetime of the battery. 50, 2 Na 0.76 V Salt bridge Cu²+26 Cu(s) +0.34 V Cu Zn(s) SO, 2² SO, Zinc (anode) Zn(s)- Zn²+20 +0.76 V Zn²+ Cu(s) a. Modify your device to operate at a lower voltage. b. Increase the concentration of CuSO4 in the electrolyte. c. Increase the size of the Zn anode.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**10. Battery Analysis and Enhancement Strategies** Consider the battery below, containing 1M CuSO₄ and 1M ZnSO₄, which is capable of delivering a voltage of 1.10V. You need this voltage to operate your device. Eventually, the battery will stop functioning as the voltage will drop to near zero. What can you do to extend the lifetime of the battery? - **a.** Modify your device to operate at a lower voltage. - **b.** Increase the concentration of CuSO₄ in the electrolyte. - **c.** Increase the size of the Zn anode. **Diagram Explanation:** - The diagram illustrates a galvanic cell. It consists of two separate beakers/containers. - On the left side, the container holds a copper (Cu) electrode submerged in a 1M CuSO₄ solution. The standard electrode potential is shown as +0.34V. - On the right side, the container holds a zinc (Zn) anode immersed in a 1M ZnSO₄ solution. The standard electrode potential is marked as -0.76V. - An external wire connects the copper and zinc electrodes, allowing electron flow. - A salt bridge connects the two containers, maintaining electrical neutrality by allowing the exchange of ions. - The overall potential difference (voltage) of the battery is marked as 1.10V. This setup demonstrates a basic electrochemical cell where oxidation occurs at the Zn anode and reduction takes place at the Cu cathode.
Transcribed Image Text:**10. Battery Analysis and Enhancement Strategies** Consider the battery below, containing 1M CuSO₄ and 1M ZnSO₄, which is capable of delivering a voltage of 1.10V. You need this voltage to operate your device. Eventually, the battery will stop functioning as the voltage will drop to near zero. What can you do to extend the lifetime of the battery? - **a.** Modify your device to operate at a lower voltage. - **b.** Increase the concentration of CuSO₄ in the electrolyte. - **c.** Increase the size of the Zn anode. **Diagram Explanation:** - The diagram illustrates a galvanic cell. It consists of two separate beakers/containers. - On the left side, the container holds a copper (Cu) electrode submerged in a 1M CuSO₄ solution. The standard electrode potential is shown as +0.34V. - On the right side, the container holds a zinc (Zn) anode immersed in a 1M ZnSO₄ solution. The standard electrode potential is marked as -0.76V. - An external wire connects the copper and zinc electrodes, allowing electron flow. - A salt bridge connects the two containers, maintaining electrical neutrality by allowing the exchange of ions. - The overall potential difference (voltage) of the battery is marked as 1.10V. This setup demonstrates a basic electrochemical cell where oxidation occurs at the Zn anode and reduction takes place at the Cu cathode.
Expert Solution
Step 1: Step 1 of 2

In the given condition .It shows a galvanic cell with a copper anode and a zinc cathode, immersed in solutions of copper sulfate and zinc sulfate, respectively. The cell is capable of delivering a voltage of 1.104 V.

This question asks how to extend the lifetime of the battery.


The diagram  shows the following half-cell reactions:

Zinc(anode):Zn→Zn2++2e−(E°=−0.76V)

Copper(cathode):Cu2++2e−→Cu(E°=0.34V)


These half-cell reactions can be combined to calculate the overall voltage of the cell:

E°cell=E°cathode−E°anode=0.34V−(−0.76V)=1.104V


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