10. Consider the battery below containing IM CuSO4 and 1MZnSO4 which is capable delivering a voltage of 1.104 V. You need this voltage to operate your device. Eventually the battery will stop functioning as the voltage will drops to near zero. What can you do to extend the lifetime of the battery. 50, 2 Na 0.76 V Salt bridge Cu²+26 Cu(s) +0.34 V Cu Zn(s) SO, 2² SO, Zinc (anode) Zn(s)- Zn²+20 +0.76 V Zn²+ Cu(s) a. Modify your device to operate at a lower voltage. b. Increase the concentration of CuSO4 in the electrolyte. c. Increase the size of the Zn anode.

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10. Consider the battery below containing 1M CuSO4 and 1MZnSO4 which is capable delivering
a voltage of 1.104 V. You need this voltage to operate your device. Eventually the battery
will stop functioning as the voltage will drops to near zero. What can you do to extend the
lifetime of the battery.
SO.
2 Na
0.76 V
Salt bridge
Cu²+2 Cu(s) +0.34 V
Cu Zn(s)
2
Zinc
(anode)
Zn(s) Zn²+20 +0.76 V
Zn²+ Cu(s)
a. Modify your device to operate at a lower voltage.
b. Increase the concentration of CuSO4 in the electrolyte.
C. Increase the size of the Zn anode.
Transcribed Image Text:10. Consider the battery below containing 1M CuSO4 and 1MZnSO4 which is capable delivering a voltage of 1.104 V. You need this voltage to operate your device. Eventually the battery will stop functioning as the voltage will drops to near zero. What can you do to extend the lifetime of the battery. SO. 2 Na 0.76 V Salt bridge Cu²+2 Cu(s) +0.34 V Cu Zn(s) 2 Zinc (anode) Zn(s) Zn²+20 +0.76 V Zn²+ Cu(s) a. Modify your device to operate at a lower voltage. b. Increase the concentration of CuSO4 in the electrolyte. C. Increase the size of the Zn anode.
Expert Solution
Step 1: Step 1 of 2

In the given condition .It shows a galvanic cell with a copper anode and a zinc cathode, immersed in solutions of copper sulfate and zinc sulfate, respectively. The cell is capable of delivering a voltage of 1.104 V.

This question asks how to extend the lifetime of the battery.


The diagram  shows the following half-cell reactions:

Zinc(anode):ZnZn2++2e(E°=0.76V)

Copper(cathode):Cu2++2eCu(E°=0.34V)


These half-cell reactions can be combined to calculate the overall voltage of the cell:

E°cell=E°cathodeE°anode=0.34V(0.76V)=1.104V


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