10. Calculate the pH of a 1.6 M solution of aniline salt (K, (aniline) = 4.3 x 1019). N: H H Aniline Aniline Salt

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**Problem 10: Calculation of pH for Aniline Salt Solution**

Given:

- Concentration of aniline salt solution = 1.6 M
- \( K_b \) (aniline) = \( 4.3 \times 10^{-10} \)

**Molecular Structures:**

1. **Aniline Salt (left diagram):**

   - Benzene ring attached to a nitrogen ion (NH\(_3^+\)).
   - The nitrogen has a positive charge, indicating it has accepted an extra proton.

2. **Aniline (right diagram):**

   - Benzene ring attached to an amine group (NH\(_2\)).
   - The nitrogen has a lone pair of electrons. 

To calculate the pH of the solution, you will need to determine the \( K_a \) of the aniline salt using the relationship \( K_w = K_a \times K_b \), where \( K_w = 1 \times 10^{-14} \).

Further steps involve calculating the concentration of H\(^+\) ions in the solution using the formula for the hydrolysis of the cation and then determining the pH using the formula:

\[ \text{pH} = -\log[H^+] \] 

### Explanation:

- **Aniline Salt:** The aniline molecule has accepted a proton, forming a positively charged ion, indicating it is in its salt form.
- **Aniline:** The base form of the molecule, with a neutral nitrogen atom possessing a lone pair of electrons.

Understanding these structures and relationships allows for an accurate calculation of the pH of the aniline salt solution.
Transcribed Image Text:**Problem 10: Calculation of pH for Aniline Salt Solution** Given: - Concentration of aniline salt solution = 1.6 M - \( K_b \) (aniline) = \( 4.3 \times 10^{-10} \) **Molecular Structures:** 1. **Aniline Salt (left diagram):** - Benzene ring attached to a nitrogen ion (NH\(_3^+\)). - The nitrogen has a positive charge, indicating it has accepted an extra proton. 2. **Aniline (right diagram):** - Benzene ring attached to an amine group (NH\(_2\)). - The nitrogen has a lone pair of electrons. To calculate the pH of the solution, you will need to determine the \( K_a \) of the aniline salt using the relationship \( K_w = K_a \times K_b \), where \( K_w = 1 \times 10^{-14} \). Further steps involve calculating the concentration of H\(^+\) ions in the solution using the formula for the hydrolysis of the cation and then determining the pH using the formula: \[ \text{pH} = -\log[H^+] \] ### Explanation: - **Aniline Salt:** The aniline molecule has accepted a proton, forming a positively charged ion, indicating it is in its salt form. - **Aniline:** The base form of the molecule, with a neutral nitrogen atom possessing a lone pair of electrons. Understanding these structures and relationships allows for an accurate calculation of the pH of the aniline salt solution.
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