2. Calculate the pH of a solution that contains 150 mL of 0.25 M NaF and 252 ml of 0.30 M HF. K, = 3.5 x 104

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**Problem: Calculate the pH of a Solution**

Calculate the pH of a solution that contains 150 mL of 0.25 M NaF and 252 mL of 0.30 M HF.

Given:
\[ K_a = 3.5 \times 10^{-4} \]

**Solution Explanation:**

To solve this problem, you need to determine the concentration of hydrogen ions (\([H^+]\)) in the solution to find the pH. This involves using the concept of a buffer solution since the solution contains both a weak acid (HF) and its conjugate base (NaF).

1. **Convert Volume to Liters:**
   - Volume of NaF: \(0.150 \, \text{L}\)
   - Volume of HF: \(0.252 \, \text{L}\)

2. **Calculate the Number of Moles:**
   - Moles of NaF: \(0.150 \, \text{L} \times 0.25 \, \text{M} = 0.0375 \, \text{moles}\)
   - Moles of HF: \(0.252 \, \text{L} \times 0.30 \, \text{M} = 0.0756 \, \text{moles}\)

3. **Calculate Concentrations in the Mixture:**
   - Total Volume \(= 0.150 \, \text{L} + 0.252 \, \text{L} = 0.402 \, \text{L}\)
   - Concentration of NaF: \(\frac{0.0375 \, \text{moles}}{0.402 \, \text{L}} \approx 0.0933 \, \text{M}\)
   - Concentration of HF: \(\frac{0.0756 \, \text{moles}}{0.402 \, \text{L}} \approx 0.188 \, \text{M}\)

4. **Apply the Henderson-Hasselbalch Equation:**

\[
\text{pH} = \text{pK}_a + \log\left(\frac{[\text{A}^-]}{[\text{HA}]}\right)
\]

   - \(\text{pK}_a = -\
Transcribed Image Text:**Problem: Calculate the pH of a Solution** Calculate the pH of a solution that contains 150 mL of 0.25 M NaF and 252 mL of 0.30 M HF. Given: \[ K_a = 3.5 \times 10^{-4} \] **Solution Explanation:** To solve this problem, you need to determine the concentration of hydrogen ions (\([H^+]\)) in the solution to find the pH. This involves using the concept of a buffer solution since the solution contains both a weak acid (HF) and its conjugate base (NaF). 1. **Convert Volume to Liters:** - Volume of NaF: \(0.150 \, \text{L}\) - Volume of HF: \(0.252 \, \text{L}\) 2. **Calculate the Number of Moles:** - Moles of NaF: \(0.150 \, \text{L} \times 0.25 \, \text{M} = 0.0375 \, \text{moles}\) - Moles of HF: \(0.252 \, \text{L} \times 0.30 \, \text{M} = 0.0756 \, \text{moles}\) 3. **Calculate Concentrations in the Mixture:** - Total Volume \(= 0.150 \, \text{L} + 0.252 \, \text{L} = 0.402 \, \text{L}\) - Concentration of NaF: \(\frac{0.0375 \, \text{moles}}{0.402 \, \text{L}} \approx 0.0933 \, \text{M}\) - Concentration of HF: \(\frac{0.0756 \, \text{moles}}{0.402 \, \text{L}} \approx 0.188 \, \text{M}\) 4. **Apply the Henderson-Hasselbalch Equation:** \[ \text{pH} = \text{pK}_a + \log\left(\frac{[\text{A}^-]}{[\text{HA}]}\right) \] - \(\text{pK}_a = -\
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