10. Analyse the beam as shown in fig. and draw the SFD and BMD. GIVEN DATA: As shown fig. A 4 KN/M 3 M- |B 1 m SKN C 1 m I + I SIMPLY SUPPORTED BEAM M T I 3KN/M 2 m E لام

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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**Problem Statement:**

10. Analyse the beam as shown in the figure and draw the Shear Force Diagram (SFD) and Bending Moment Diagram (BMD).

**GIVEN DATA:**
As shown in the figure.

**Beam Description:**

- The beam is a simply supported beam with support reactions at RA and RE.
- **Load Distribution:**
  - A triangular distributed load starts at point A and ends at point B with an intensity of 4 kN/m.
  - A point load of 5 kN is applied downward at point C.
  - A uniform distributed load of 3 kN/m is applied between points D and E.

**Beam Dimensions:**

- AB = 3 m
- BC = 1 m
- CD = 1 m
- DE = 2 m
- The total length of the beam is 5 m.

**Diagram Explanation:**

- **Triangular Load (AB):** The load begins at zero at point A and increases linearly to 4 kN/m at point B.
- **Point Load (C):** A concentrated load is applied vertically downward at point C.
- **Uniform Distributed Load (DE):** A consistent load of 3 kN/m is applied across the span from D to E.

This description can help in understanding the setup before performing structural analysis to develop the Shear Force Diagram and Bending Moment Diagram for the beam.
Transcribed Image Text:**Problem Statement:** 10. Analyse the beam as shown in the figure and draw the Shear Force Diagram (SFD) and Bending Moment Diagram (BMD). **GIVEN DATA:** As shown in the figure. **Beam Description:** - The beam is a simply supported beam with support reactions at RA and RE. - **Load Distribution:** - A triangular distributed load starts at point A and ends at point B with an intensity of 4 kN/m. - A point load of 5 kN is applied downward at point C. - A uniform distributed load of 3 kN/m is applied between points D and E. **Beam Dimensions:** - AB = 3 m - BC = 1 m - CD = 1 m - DE = 2 m - The total length of the beam is 5 m. **Diagram Explanation:** - **Triangular Load (AB):** The load begins at zero at point A and increases linearly to 4 kN/m at point B. - **Point Load (C):** A concentrated load is applied vertically downward at point C. - **Uniform Distributed Load (DE):** A consistent load of 3 kN/m is applied across the span from D to E. This description can help in understanding the setup before performing structural analysis to develop the Shear Force Diagram and Bending Moment Diagram for the beam.
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