10. A projectile is launched with an initial speed of 166.0m/s at an angle of 55.0° above the horizontal. (a)If the time of flight is 42 s, what are the x and y coordinates at impact? b.) what is the impact velocity?
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- 7. A basketball player is running at 4.80 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains his horizontal velocity. (For each answer, enter a number.) (a) What vertical velocity (in m/s) does he need to rise 0.750 meters above the floor? m/s (b) How far (in m) from the basket (measured in the horizontal direction) must he start his jump to reach his maximum height at the same time as he reaches the basket? m Submit OpcworTwo projectiles are launched from the same point at the same angle, but the first one has twice the initial velocity compared to the second. The ranges R1 and R2 are: O A. R2 = 4R1 O B. R1 = 4R2 OC R2= 2R1 OD R1 = R2 O E None of the above.An arrow is launched from ground level, with an initial speed of 27.2 m/s at an angle of 31.4° above the horizontal. Neglect air resistance, and take upward as the positive direction. a) How much time is needed for the arrow to reach its maximum height, b) what is this maximum heightc) how long does it take to land on the ground againd) how far does it travel right before it lands.
- IRain is falling steadily, but there is no wind. You are on a bus that moves at 50.0 km/hr, and you see that the rain appears to be falling at an angle of 31o with respect to the vertical. What is the vertical velocity of the rain drops?The initial speed of a tennis ball is 57.5 m/s and the launch angle is ?i = 16°. Neglect air resistance.Question 1) What is the maximum height, h, of the tennis ball? in mQuestione 2) What is the range, R, of the tennis ball? in m info given: what angle results in the greatest height=90 For this 90° angle, the horizontal component of velocity is zero, so the initial velocity is completely in the vertical direction, resulting in greatest height Kato tries substituting ty,max for t, 0 for yi, and h for yf, and gets h = vi2 sin2 ?i 2g When ?i = 90°, sin2 ?i is maximum, so h is maximum what angle results in the maximum horizontal range=45° I substituted 2vi sin ?i g into the expression for the horizontal component of velocity, (vi cos ?i)t, and got R = 2vi2 sin ?i cos ?i g when ?i = 45°, 2?i = 90°, and sin 90° = 1, which is its maximum value.
- 1. A player lines up to kick a 40 m goal. In the first attempt, the ball has an initial velocity of 20 m/s at angle of 55.0 degrees. The goal posts are 3 m high. Ônce the ball passes above the field goal post (i.e., after it has travelled 40 m in the horizontal direction), it is deemed successful. (a) Determine if the goal kicker's first attempt is successful. (b) If the kicker changes the angle of kicking to 30 degrees and the initial velocity so that it JUST reaches the goal post. Determine the new initial velocity of ball.Please answer the following. If not then answer number 3 only.