10. A compound tube is formed by shrinking together two tubes with common radius 150 mm and thickness 25 mm. The shrinkage allowance is to be such that when an internal pressure of 30 MN/m² (300 bar) is applied the final maximum stress in each tube is to be the same. Determine the value of this stress. What must have been the difference in diameters of the tubes before shrinkage? E=210 GN/m².

10. A compound tube is formed by shrinking together two tubes with common radius 150 mm and thickness 25 mm. The shrinkage allowance is to be such that when an internal pressure of 30 MN/m² (300 bar) is applied the final maximum stress in each tube is to be the same. Determine the value of this stress. What must have been the difference in diameters of the tubes before shrinkage? E=210 GN/m².

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Pressure Vessels

The term pressure vessel refers to a closed container that contains gas or liquid at a different pressure than environment pressure. The pressure vessels have a wide scale of applications in our day-to-day lives and other industrial places. Some common examples of pressure vessels are gas cylinders, autoclaves, compressor vessels, etc.

Question

10. A compound tube is formed by shrinking together two tubes with common
radius 150 mm and thickness 25 mm. The shrinkage allowance is to be such that
when an internal pressure of 30 MN/m² (300 bar) is applied the final maximum
stress in each tube is to be the same. Determine the value of this stress. What must
have been the difference in diameters of the tubes before shrinkage? E=210 GN/m².

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Step 1: Given Data

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Step 2: The expression for hoop stress

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Step 3: Expression for hoop stress at common radius

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Step 4: For the outer tube

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