10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters ofsolution. Calculate the Molarity of HCl, the [H+], and the pH of the solution. 10. M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829 Show step by step solutions 11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution [H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M Show step by step solutions
10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters ofsolution. Calculate the Molarity of HCl, the [H+], and the pH of the solution. 10. M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829 Show step by step solutions 11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution [H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M Show step by step solutions
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters of
solution. Calculate the Molarity of HCl, the [H+], and the pH of the solution.
10. M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829
Show step by step solutions
11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution
[H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M
Show step by step solutions
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