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10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters ofsolution. Calculate the Molarity of HCl, the [H+], and the pH of the solution. 10.  M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829 Show step by step solutions  11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution [H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M Show step by step solutions

10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters ofsolution. Calculate the Molarity of HCl, the [H+], and the pH of the solution. 10.  M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829 Show step by step solutions  11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution [H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M Show step by step solutions

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter14: Acids And Bases
Section: Chapter Questions
Problem 32QRT
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10) A solution is created by dissolving 14.2 grams of HCl (a strong acid) into water, making 2.63 Liters of
solution. Calculate the Molarity of HCl, the [H+], and the pH of the solution.

10.  M HCl = 0.148 M / [H+] = 0.148 M / pH = 0.829

Show step by step solutions 


11) A basic solution is prepared to a measured pH of 12.45. Calculate the [OH-] and the [H+] of this solution

[H+] = 3.548 x 10-13 M / [OH -] = 2.818 x 10-2 M

Show step by step solutions  

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