Answer all parts A chemist needs a buffer with pH 5.11. How many millilitersof pure acetic acid (density = 1.049 g/mL) must be added to498 mL of7.17 x 10-² MNaOH solution to obtain such a buffer?Ka (acetic acid) = 1.8 × 10-5Volume =mL The pH of a household cleaning solution is 11.79. Thiscleanser is an aqueous solution of ammonia with a densityof 1.00 g/mL. What is the mass percentage of ammonia inthe solution?K₂ (NH3) = 1.8 × 10-5Mass percentage =%

The question belongs to the general physical chemistry.

A chemist needs a buffer with pH 5.11. How many milliliters of pure acetic acid (density = 1.049 g/mL) must be added to 498 mL of 7.17 x 10-² M NaOH solution to obtain such a buffer? Ka (acetic acid) = 1.8 x 10-5 Volume = mL

A chemist needs a buffer with pH 5.11. How many milliliters of pure acetic acid (density = 1.049 g/mL) must be added to 498 mL of 7.17 x 10-² M NaOH solution to obtain such a buffer? Ka (acetic acid) = 1.8 x 10-5 Volume = mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Answer all parts

A chemist needs a buffer with pH 5.11. How many milliliters
of pure acetic acid (density = 1.049 g/mL) must be added to
498 mL of
7.17 x 10-² M
NaOH solution to obtain such a buffer?
Ka (acetic acid) = 1.8 × 10-5
Volume =
mL

The pH of a household cleaning solution is 11.79. This
cleanser is an aqueous solution of ammonia with a density
of 1.00 g/mL. What is the mass percentage of ammonia in
the solution?
K₂ (NH3) = 1.8 × 10-5
Mass percentage =
%

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