10-240° V C n a 1020° V ial 36-18 Ω Vab in 6-j80 6-j8N Ω 10-120° V Vca b ibl 1 Vbc icl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial = ibl = id = Vab = Ubc = Vca = L л л O 0 A A 0 A ° V 4 ° V ° V
10-240° V C n a 1020° V ial 36-18 Ω Vab in 6-j80 6-j8N Ω 10-120° V Vca b ibl 1 Vbc icl Find the line currents and line-to-line voltages. (Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2 digits) ial = ibl = id = Vab = Ubc = Vca = L л л O 0 A A 0 A ° V 4 ° V ° V
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter8: Symmetrical Components
Section: Chapter Questions
Problem 8.1P
Related questions
Question
Transcribed Image Text:10-240° V
C
n
a
1020° V
ial
36-18 Ω
Vab
in
6-j80 6-j8N
Ω
10-120° V
Vca
b
ibl
1
Vbc
icl
Find the line currents and line-to-line voltages.
(Positive magnitudes) (Phase angles between ±180°) (Round decimal answers to 2
digits)
ial
=
ibl
=
id =
Vab
=
Ubc
=
Vca =
L
л
л
O
0
A
A
0
A
° V
4
° V
° V
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