10 20 30 50 70 80 90 X3 X2 O. loo kg- 0. 050 kg 0.750 kg.

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Make a free body diagram according to the given data

Mass (kg)
Position (m)
Lever arm (m)
Torque (N-m)
% Difference
m = 0.100
X1 = 0.100
di =0.405
Tccw= 0.399
m, = 0.200
X2 =0.750
d2 =0.245
Tcw= 0.480
%3D
m; = 0.050
X3 =0.500
d3 =0.005
18.43%
Transcribed Image Text:Mass (kg) Position (m) Lever arm (m) Torque (N-m) % Difference m = 0.100 X1 = 0.100 di =0.405 Tccw= 0.399 m, = 0.200 X2 =0.750 d2 =0.245 Tcw= 0.480 %3D m; = 0.050 X3 =0.500 d3 =0.005 18.43%
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20
X3
Xz
O. loo kg.
0. 050kg
0.750 kg.
Transcribed Image Text:10 30 40 50 60 70 80 90 20 X3 Xz O. loo kg. 0. 050kg 0.750 kg.
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