1.What will be the new vapor pressure of the water in a 250 mL solution of 0.3774M solution of Na2Co3 (MW=105.99 g/mol) with a density of 1.2 g/ml?The Vapor pressure of water is 23.8 mmhg at 25°c

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1.What will be the new vapor pressure of the water in a 250 mL solution of 0.3774M solution
of Na2Co3 (MW=105.99 g/mol) with a density of 1.2 g/ml?The Vapor pressure of water is 23.8
mmhg at 25°c
2.What will be the new vapor pressure of the water in a 100 mL solution of 10 g of sugar
(MW= 342.3 g/mol) with a density of 1.04 g/ml? The Vapor pressure of water ins 23.8 mmHg
at 25°c
3.
A 5 gram (NH4)2sO4 (MW = 132.14 g/mol) was dissolved to make 500mL solution. It found to have a
density of 1.05 mL at 25°C. Find its concentration in:
Molarity (M) = [A]
Normality (N) = [B]
%3D
Molality (m) = [C]
A 100 mL solution was prepared by dissolving 10.00 g of Caso4 (MW= 136. 14 g/mol) in water. The
density of the solution was found to be 1.15 g/ml at 25°C. Find the new boiling and freezing
temperature of water in this solution.
Answers in 2 decimal places. no need to write the unit.
New boiling point [A]
New Freezing point = [B]
%3!
Transcribed Image Text:1.What will be the new vapor pressure of the water in a 250 mL solution of 0.3774M solution of Na2Co3 (MW=105.99 g/mol) with a density of 1.2 g/ml?The Vapor pressure of water is 23.8 mmhg at 25°c 2.What will be the new vapor pressure of the water in a 100 mL solution of 10 g of sugar (MW= 342.3 g/mol) with a density of 1.04 g/ml? The Vapor pressure of water ins 23.8 mmHg at 25°c 3. A 5 gram (NH4)2sO4 (MW = 132.14 g/mol) was dissolved to make 500mL solution. It found to have a density of 1.05 mL at 25°C. Find its concentration in: Molarity (M) = [A] Normality (N) = [B] %3D Molality (m) = [C] A 100 mL solution was prepared by dissolving 10.00 g of Caso4 (MW= 136. 14 g/mol) in water. The density of the solution was found to be 1.15 g/ml at 25°C. Find the new boiling and freezing temperature of water in this solution. Answers in 2 decimal places. no need to write the unit. New boiling point [A] New Freezing point = [B] %3!
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