1. Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance

1. Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern. The angle to the eighth maximum is 1.12°. The distance from the slits to the screen is 302.0 cm. The distance from the central maximum to the fifth minimum is 3.33 cm. The distance

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13. Suppose that you have a laser of wavelength 2 = 450 nm, and a single slit with a width of a = 0.16 mm. You plan to place the slit exactly L = 1.00 m away from a viewing screen, but you want to predict the positions of the dark fringes in advance. First, let's check if the small-angle approximation applies to this situation. a. Use på a sin 0 to calculate the angle 8₁ for the first order (p = 1) dark fringes: = b. Calculate sin 0₁: c. Calculate tan 0₁: d. Compare the values for sin 0, and tan 8₁. Are these approximately equal? If so, then we can use the small angle approximation 0, (rad) ≈ P²P for further R a L calculations, and the dark fringes should be equally spaced. S 2015 #10772/ 754911 My PORTALLA 1500 ALTERNA
1. Pick True/False for each statement: To experimentally see the interference pattern in Young's double slit experiment, a) the barriers creating diffraction or interference are on the scale of a wavelength of light. True False b) the two slits can be lit with different sources. True False c) the light is monochromatic. True False
The spacing between two slits is 5.90×10^-3 m in a Young's double slit experiment. The distance from the slits to the screen is 1.00 m, and the distance from the central bright maximum to the third maxima is 2.50x10^-4 m. Determine the wavelength of the incident light used in the experiment. Include a labelled diagram.
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10. You have a single-slit diffraction apparatus, with a slit 4.60 × 10−6 m wide arranged 1.80 m from the screen. You would like an anti-node to appear 68.2 cm from the right bisector. What are two possible visible wavelengths you could use?
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5. Draw the variation of the mean light intensity (l) with respect to the angle of diffraction (teta) if i is due to interference of light of wavelength (lamda) using 2 slits. It is known that each slit has a width of a(- 2 lamda) and the distance between the two slits is d(- 4 lamda).
1. a) Your teacher produces a light interference pattern on the wall. How will you identify whether the pattern is being created by a single, double, or multiple slit apparatus? b) Use the single slit simulator to validate the equations learned in this activity related to single-slit diffraction. Use the simulator to obtain measurements, and then show complete calculations of the wavelength of light using all five of the single-slit equations. (Note that you will have to calculate the angle using the sine function.) Choose any set-up you desire in terms of distance to the screen, the width of the slit, and wavelength. How do your calculated wavelengths compare to the wavelength given in the simulation? c) When white light, composed of all wavelengths (as opposed to monochromatic light that is composed of one wavelength of light), is shone through a diffraction grating, bands of various colours appear on the screen. For example, there may be first-order (m = 1) fringes for red, orange,…
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In a Young's double slit experiment the wavelength of light is ?λ, separation between the slits is ?a and the distance to the screen is ?D. Give an expression for the interference fringe width ?w on screen if ?≫?D≫a. For Greek letters such as ?λ use the text equivalent - e.g. "lambda" (without the quotes, e.f. for ??Dλ use D*lambda).