1.char sta[80];2.char text[80]="This is the value";3.char* ptext="Sample string";4.char output[120];5.puts(text)3B6.printf(“%s",text);Illustration 6: Ch 8 46. Illustration 6: Which line declares a string (char array)with maximum 80 characters, initialized to a string?A. 1В. 2C. 4D. 647. Illustration 6: Which line just creates an array useful for80 characters?A. 4В. 6C. 5D. 1

Answered: 1.char sta[80]; 2.char text[80]="This…

1.char sta[80]; 2.char text[80]="This is the value"; 3.char* ptext="Sample string"; 4.char output[120]; 5.puts(text), 6.printf("%s",text)3B 55

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

See similar textbooks

Similar questions

Assume the constant SIZE has value 16. What will the following program segment display? char string1[SIZE] = "Have a "; char string2[] = "nice day"; strcat(string1, string2); cout << string1 << endl;cout << string2 << endl;
5) Which of the following is a legal way to declare and instantiate an array of 10 Strings?a) String s = new String(10);b) String[10] s = new String;c) String[ ] s = new String[10];d) String s = new String[10];e) String[ ] s = new String;
C++ PLEASE!! // FILE: simplestring.h// CLASS PROVIDED: string (a sequence of characters)//// CONSTRUCTOR for the string class:// string(const char str[ ] = "") -- default argument is the empty string.// Precondition: str is an ordinary null-terminated string.// Postcondition: The string contains the sequence of chars from str.//// CONSTANT MEMBER FUNCTIONS for the string class:// size_t length( ) const// Postcondition: The return value is the number of characters in the// string.//// char operator [ ](size_t position) const// Precondition: position < length( ).// Postcondition: The value returned is the character at the specified// position of the string. A string's positions start from 0 at the start// of the sequence and go up to length( )-1 at the right end.//// MODIFICATION MEMBER FUNCTIONS for the string class:// void operator +=(const string& addend)// Postcondition: addend has been catenated to the end of the string.//// void operator +=(const char addend[ ])//…
#include using namespace std; void scanPrice (string [], double []); // Do not modify the code double printReceipt(string [], double[]); // Do not modify the code int main () { double sum; string item [3] = {"Vegetable","Egg", "Meat"}; double price [3];| %3D scanPrice (item,price); sum = RrintReceipt (item,price); cout Price: 10 The price of Vegetable is RM 2 The price of Egg is RM 3 The price of Meat is RM 10 Your total expenses is RM 15
Select all the correct ways to declare * a string char name; int name[100]; char name[20]; char a[100]; D int a[100]; char a; U
Initialize a vector v1 with the following values: 0 23 -7 8 -22 3 14 Write a MATLAB program from the values in v1. The vector v2 should contain the values in v1 transformed as follows: that uses a for-loop and if-statements to make a new vector v2 multiply each positive even element in v1 by 3, multiply each positive odd element of v1 by -2, and change the sign of the negative elements in v1. Then, output the new vector to the command window as follows: The new vector is: -46 7 24 22 -6 42 Also, compute and output the mean of the values in the new vector: The mean of the new vector is: xxxx Above, xxxx is the mean of the values in the new vector with 1 decimal place.
The string "slots" that are filled in by the format method are marked by:a) % b) $ c) [] d) {}
L = [[[1,2], [3,4,5]], "friday", {'x': "halloween", 'y':7, 'z’:77}, {10, 11, 12}] Show the commands for the following operations on L a) retrieve 'w' inside string "halloween" b) retrieve 4 c) retrieve 'y' in string "friday" d) change the value of key 'z' to 100 e) place 'A' inside [3, 4, 5] f) place 'B' inside {10, 11, 12}
Given code line, std::string un_address = "405 East 42nd Street, New York, NY, 10017"; Fill in the blanks: 17 std::stoi(un_address) returns std::stoi (un_address.substr( std::stoi (un_address.substr(un_address.find("1"))) J 20)) returns 42 returns
Help plz