1.7.2 Example B Prove the following (Newton's theorem): If fk is a polynomial of the nth degree, then it can be written in the form fk = fo + Afo (1) + A°fo (2) A" fo pln). 1! +...+ n! (1.186) 2! Assume that fk has the representation fk = ao + a1k) + azk(2) + ... + ankn), (1.187) where ao, a1,..., an are constants. Differencing fk n times gives Afk = a1 + 2azk(1) + 3azk(2) +... A² fk = 2·1. a2 + 3. 2. azk(1) +... + па,k(п-1), +n(n – 1)ank(n-2), (1.188) A" fk = ann(n – 1) ·. - (1). THE DIFFERENCE CALCULUS 25 Setting k = 0 in the original function and its differences allows us to conclude that Am fo am = т %3D 0, 1, ...., п. (1.189) т! To illustrate the use of this theorem, consider the function fk = k4. (1.190) Now Afk = 4k3 + 6k² + 4k + 1, A² fk = 12k2 + 24k + 14, A³ fk = 24k + 36, Aª fk = 24, (1.191)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
icon
Related questions
icon
Concept explainers
Question

Explain this

1.7.2
Example B
49
Prove the following (Newton's theorem): If fk is a polynomial of the nth
degree, then it can be written in the form
fk = fo +
Afo 1(1) + A-Jo k(2) + ..
A" fo 1(1).
(1.186)
1!
2!
n!
Assume that fk has the representation
fk = ao + a1k(1) + a2k(2) +… ..
+ ank(n),
(1.187)
where ao, a1,..., an are constants. Differencing fk n times gives
= a1 + 2a2k(1) + 3azk(2) + ·..
+ nank(n-1).
A² fk = 2·1. a2 + 3· 2. azk) +..
+ n(n – 1)a,k(n–2),
(1.188)
A" fk = ann(n – 1)· . · (1).
THE DIFFERENCE CALCULUS
25
Setting k
= 0 in the original function and its differences allows us to conclude
that
A™ fo
Am =
m = 0,1,...., n.
(1.189)
т!
To illustrate the use of this theorem, consider the function
fk = k4.
(1.190)
Now
Afk = 4k3 + 6k² + 4k + 1,
A² fk = 12k? + 24k + 14,
(1.191)
A³ fk = 24k + 36,
Aª fk = 24,
and
Transcribed Image Text:1.7.2 Example B 49 Prove the following (Newton's theorem): If fk is a polynomial of the nth degree, then it can be written in the form fk = fo + Afo 1(1) + A-Jo k(2) + .. A" fo 1(1). (1.186) 1! 2! n! Assume that fk has the representation fk = ao + a1k(1) + a2k(2) +… .. + ank(n), (1.187) where ao, a1,..., an are constants. Differencing fk n times gives = a1 + 2a2k(1) + 3azk(2) + ·.. + nank(n-1). A² fk = 2·1. a2 + 3· 2. azk) +.. + n(n – 1)a,k(n–2), (1.188) A" fk = ann(n – 1)· . · (1). THE DIFFERENCE CALCULUS 25 Setting k = 0 in the original function and its differences allows us to conclude that A™ fo Am = m = 0,1,...., n. (1.189) т! To illustrate the use of this theorem, consider the function fk = k4. (1.190) Now Afk = 4k3 + 6k² + 4k + 1, A² fk = 12k? + 24k + 14, (1.191) A³ fk = 24k + 36, Aª fk = 24, and
Expert Solution
steps

Step by step

Solved in 4 steps

Blurred answer
Knowledge Booster
Points, Lines and Planes
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Advanced Engineering Mathematics
Advanced Engineering Mathematics
Advanced Math
ISBN:
9780470458365
Author:
Erwin Kreyszig
Publisher:
Wiley, John & Sons, Incorporated
Numerical Methods for Engineers
Numerical Methods for Engineers
Advanced Math
ISBN:
9780073397924
Author:
Steven C. Chapra Dr., Raymond P. Canale
Publisher:
McGraw-Hill Education
Introductory Mathematics for Engineering Applicat…
Introductory Mathematics for Engineering Applicat…
Advanced Math
ISBN:
9781118141809
Author:
Nathan Klingbeil
Publisher:
WILEY
Mathematics For Machine Technology
Mathematics For Machine Technology
Advanced Math
ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,
Basic Technical Mathematics
Basic Technical Mathematics
Advanced Math
ISBN:
9780134437705
Author:
Washington
Publisher:
PEARSON
Topology
Topology
Advanced Math
ISBN:
9780134689517
Author:
Munkres, James R.
Publisher:
Pearson,