1.6 Three positive charges, A, B, and C, of 3 × 10-6, 2 × 10-“, and 2 X 10-6 coulombs, respectively, are located at the corners of an equilateral triangle of side 0.2 meter. (a) Find the magnitude in newtons of the force on each charge. (b) Find the magnitude in newtons/coulomb of the electric field at the center of the triangle. (a) 2.34 newtons on A, 1.96 newtons on B and C; (b) 6.74 X 10° newtons/coulomb. Ans.

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Please see image below. Answer both parts. Answers are in the question, but please show your steps.

1.6 Three positive charges, A, B, and C, of 3 x 10-6, 2 × 10-“,
and 2 X 10-6 coulombs, respectively, are located at the corners of an
equilateral triangle of side 0.2 meter.
(a) Find the magnitude in newtons of the force on each charge.
(b) Find the magnitude in newtons/coulomb of the electric field
at the center of the triangle.
Ans.
(a) 2.34 newtons on A, 1.96 newtons on B and C;
(b) 6.74 X 10° newtons/coulomb.
Transcribed Image Text:1.6 Three positive charges, A, B, and C, of 3 x 10-6, 2 × 10-“, and 2 X 10-6 coulombs, respectively, are located at the corners of an equilateral triangle of side 0.2 meter. (a) Find the magnitude in newtons of the force on each charge. (b) Find the magnitude in newtons/coulomb of the electric field at the center of the triangle. Ans. (a) 2.34 newtons on A, 1.96 newtons on B and C; (b) 6.74 X 10° newtons/coulomb.
Expert Solution
Step 1

Given: qA=3×10-6C, qB=2×10-6C, qC=2×10-6C, a=0.2m

(a) The forces experienced by charge A due to charges B and C are :

FBA=9×109qBqAa2=1.35NFCA=9×109qCqAa2=1.35N

The magnitude of the net force experienced by charge A is :

FA=FBA2+FCA2+2FBAFCAcosθ              θ=60°FA=1.352+1.352+2×1.35×1.35cos60FA=2.34N

Refer to the figure below :

Advanced Physics homework question answer, step 1, image 1

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