1.6 (a) 5 kN 8 kN C D 3 kN BY 30° 30° E H G F 2 m 2 m 2 m 2 m Figure 1.29 (b) Explain why the forces in BH and DF will be equal to zero. [FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T); FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN] =

Elements Of Electromagnetics
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Please explain the solution in detail,use FBD in your explanation.
1.6 (a)
5 kN
8 kN
C
D
3 kN
BY
30°
30°
E
H
G
F
2 m
2 m
2 m
2 m
Figure 1.29
(b) Explain why the forces in BH and DF will be equal to zero.
[FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T);
FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN]
=
Transcribed Image Text:1.6 (a) 5 kN 8 kN C D 3 kN BY 30° 30° E H G F 2 m 2 m 2 m 2 m Figure 1.29 (b) Explain why the forces in BH and DF will be equal to zero. [FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T); FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN] =
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