1.6 (a) 5 kN 8 kN C D 3 kN BY 30° 30° E H G F 2 m 2 m 2 m 2 m Figure 1.29 (b) Explain why the forces in BH and DF will be equal to zero. [FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T); FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN] =
1.6 (a) 5 kN 8 kN C D 3 kN BY 30° 30° E H G F 2 m 2 m 2 m 2 m Figure 1.29 (b) Explain why the forces in BH and DF will be equal to zero. [FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T); FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN] =
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Please explain the solution in detail,use FBD in your explanation.
![1.6 (a)
5 kN
8 kN
C
D
3 kN
BY
30°
30°
E
H
G
F
2 m
2 m
2 m
2 m
Figure 1.29
(b) Explain why the forces in BH and DF will be equal to zero.
[FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T);
FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN]
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feb26c97f-c83e-4e66-901e-10719ec8ef2b%2F88809292-e8e8-4a5b-a2bb-e007a4b50b1e%2Ftvxsztb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.6 (a)
5 kN
8 kN
C
D
3 kN
BY
30°
30°
E
H
G
F
2 m
2 m
2 m
2 m
Figure 1.29
(b) Explain why the forces in BH and DF will be equal to zero.
[FAB = = 17 kN (S); FCD = FBC = 12 kN (S); FFG = 13 kN (T);
FHG FAH = 14,72 kN (T); R₁ = 8,5 kN; R = 7,5 kN]
=
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