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1.22 Fill in the timing diagram for a falling-edge-triggered J-K flip-flop. Assume Q begins at 0. Assume Q begins at 1, but clock, J, and K are the same. Clock K (a) Q (b)

1.22 Fill in the timing diagram for a falling-edge-triggered J-K flip-flop. Assume Q begins at 0. Assume Q begins at 1, but clock, J, and K are the same. Clock K (a) Q (b)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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### Timing Diagram for a Falling-Edge-Triggered J-K Flip-Flop This diagram helps illustrate the behavior of a J-K flip-flop based on given clock, J, and K input signals. The J-K flip-flop is a type of digital storage element that can act as a memory for one bit of information. #### Components of the Diagram: 1. **Clock Signal**: - The clock line shows a series of square pulses. The transitions from high to low represent the falling edges, which are the triggering events for the J-K flip-flop. 2. **J Signal**: - The J line indicates when the J input is high or low. This signal determines how the flip-flop should behave on the falling edge of the clock signal. 3. **K Signal**: - The K line shows when the K input is high or low. Similar to the J input, it influences the state of the flip-flop on the clock's falling edge. 4. **Q Output** (for parts a and b): - Two scenarios are tested for the Q output, depending on the initial state of Q. - **Scenario (a)**: Q begins at 0. - **Scenario (b)**: Q begins at 1. - For each clock falling edge, the Q output is updated based on the states of J and K according to the J-K flip-flop truth table. #### Explanation: - **State Transitions**: - On the falling edge of the clock, the state of Q changes depending on the inputs J and K: - **J = 0, K = 0**: No change. - **J = 0, K = 1**: Reset Q to 0. - **J = 1, K = 0**: Set Q to 1. - **J = 1, K = 1**: Toggle Q. This diagram effectively guides students to understand how the J-K flip-flop changes state concerning the clock edge and the input signals. Filling out the Q lines for each scenario will reinforce understanding of synchronous sequential logic.
Transcribed Image Text:### Timing Diagram for a Falling-Edge-Triggered J-K Flip-Flop This diagram helps illustrate the behavior of a J-K flip-flop based on given clock, J, and K input signals. The J-K flip-flop is a type of digital storage element that can act as a memory for one bit of information. #### Components of the Diagram: 1. **Clock Signal**: - The clock line shows a series of square pulses. The transitions from high to low represent the falling edges, which are the triggering events for the J-K flip-flop. 2. **J Signal**: - The J line indicates when the J input is high or low. This signal determines how the flip-flop should behave on the falling edge of the clock signal. 3. **K Signal**: - The K line shows when the K input is high or low. Similar to the J input, it influences the state of the flip-flop on the clock's falling edge. 4. **Q Output** (for parts a and b): - Two scenarios are tested for the Q output, depending on the initial state of Q. - **Scenario (a)**: Q begins at 0. - **Scenario (b)**: Q begins at 1. - For each clock falling edge, the Q output is updated based on the states of J and K according to the J-K flip-flop truth table. #### Explanation: - **State Transitions**: - On the falling edge of the clock, the state of Q changes depending on the inputs J and K: - **J = 0, K = 0**: No change. - **J = 0, K = 1**: Reset Q to 0. - **J = 1, K = 0**: Set Q to 1. - **J = 1, K = 1**: Toggle Q. This diagram effectively guides students to understand how the J-K flip-flop changes state concerning the clock edge and the input signals. Filling out the Q lines for each scenario will reinforce understanding of synchronous sequential logic.
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