1.2 #2 2 Prove 1³ +2³+ ... +N³ = [ ½/2N (N+1)]² for all NEN show N=1 1³= 1 [1/2₂ (1) (1 +D]² >> ½/2₂ (2) → ¾/2=1 2 Assume KEN Apply Yht! 3 1³ +2³² + ... + K³ = [ ½/2₂K (K+D]² 13³ +2³3 + ... + K³ + (K+1) ³ = [ ½/₂K(K+1)] ² + (K+1) = [ ½/₂(K+1)K]²+ (K+1) 2 [ ½/2[h+1)(h+z)] ²

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